The negitives are far from the 0 so its less than the non negitives
If the position at time <em>t</em> is
<em>s(t)</em> = (1 m/s³) <em>t</em> ³
then the average velocity over <em>t</em> = 2 s and <em>t</em> = 2.001 s is
<em>v</em> (ave) = (<em>s</em> (2.001 s) - <em>s</em> (2 s)) / (2.001 s - 2 s)
<em>v</em> (ave) = ((1 m/s³) (2.001 s)³ - (1 m/s³) (2 s)³) / (2.001 s - 2 s)
<em>v</em> (ave) ≈ (8.01201 m - 8 m) / (0.001 s)
<em>v</em> (ave) ≈ 12.006 m/s
Answer:

Step-by-step explanation:
Let P% of the transaction amount is charged in the account.
So, if the transaction amount is x, then the charge for that transaction will be
.
Therefore, if f(x) represents the amount Isabel is charged for the transaction then we can write
, where P% is the rate of charge. ( Answer )
Answer:
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Step-by-step explanation: