Answer:
36
Step-by-step explanation:
First we need to find the gradient of K
which is y1-y2/x1-x2
(-1,3) and (5,-2)
so it becomes 3-(-2)/-1-5
m=-5/6
when two lines are perpendicular their gradients multiply to make -1
that means the gradient of L has to be 6/5
we can substitute the point on L (5,-2) and the gradient of 6/5 into y=mx+c
-2 = (6/5) x 5 + c
c = -8
the equation of line L is y= 6x/5 -8
Answer:
x2-7 can be the length and 6 can be the width of it and then that would l give you are l time w
Step-by-step explanation:
The first word of the question is cut out of the picture, so we don't exactly know what the assignment is. But we can see that the graph of f(x) will do something weird when x=-3, because the denominator will be zero, and division by zero doesn't even have a definition or meaning. Just for fun, you should go ahead and calculate the numerator when x=-3, and that totally blows your mind, because the numerator is zero too. So you've got. f(-3)= 0/0 , and I can pretty much guarantee that you won't be able to plot that point anywhere on the graph. (I'm pretty sure that f(-3) is actually going to turn out to be -13, but even if I'm correct, you probably haven't learned that little calculus trick yet, so don't worry about it. As far as you're concerned, f(-3) is 0/0, and can't be plotted.)
Answer:
2 over 5 (2/5)
Step-by-step explanation:
