If A(−2, 1), B(1, 5), C(4, 4), and D(1, 0) are the vertices of a quadrilateral, do the points form a parallelogram? Justify your
answer. Yes, it is a parallelogram because the slope of segment AB equals the slope of segment DC, which equals negative start fraction four over three end fraction, and AD = BC = 10 units.
Yes, it is a parallelogram because the midpoint of the diagonals segment AC and segment BD is (4.5, 2.5).
No, it is not a parallelogram because the slope of segment AB = 1 and the slope of segment DC equals negative start fraction four over three end fraction full stop
Yes, it is a parallelogram because the slope of segment AB equals the slope of segment DC, which equals start fraction four over three end fraction, and AB = DC = 5 units.
<span>Yes, it is a parallelogram because the slope of segment AB equals the slope of segment DC, which equals negative start fraction four over three end fraction, and AD = BC = 10 units.</span>
-7n + 9 because the common difference is -7, so you have -7n, and then by plugging in the term numbers and the values, you find out that you need to add 9 to the -7n, so the answer is -7n + 9
