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Ivanshal [37]
4 years ago
9

Jenny has a 5734 kg bag of dog food. Her dog eats 514 kg of food each week. How many weeks will the bag of dog food last? 1034 w

eeks 11 weeks 1838 weeks 63 weeks
Mathematics
2 answers:
rjkz [21]4 years ago
5 0

Answer:11

Step-by-step explanation:

She has 5734. He eats 514 a week so you divide 515 into 5734 to know how many weeks she’ll be able to feed the dog

5734/514=11

Vladimir79 [104]4 years ago
4 0

Answer:

11 week

Step-by-step explanation:

Since it is given that Jenny's dog eat 514 kg food per week.

And she has 5734 kg bag of food.

Thus, Total week bag of food last long = \frac{\text{Total bag of food Jenny has}}{\text{Food eaten bey dog each week}}

⇒ Number of week = \frac{5734}{514}

⇒ Number of week = 11.16 week ≈ 11 week

Hence, Total week bag of food last long is nearly 11 week.

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Sladkaya [172]
Stage B would be 70km since 5/7 is stage B and 5 x 14 = 70
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3 years ago
A life guard in a tower 20 ft above sea level spots a struggling surfer at an angle of depression of 15 . How far is the surfer
GalinKa [24]

Answer: 19.31\ ft

Step-by-step explanation:

Given

The tower is at a height of h=20\ ft

the angle of depression is 15^{\circ}

Suppose the surfer is x ft away from the base of the tower

\therefore \text{From the figure, we can write}\\\\\Rightarrow \cos 15^{\circ}=\dfrac{x}{h}\\\\\Rightarrow x=h\cos 15^{\circ}\\\Rightarrow x=20\cos 15^{\circ}\\\Rightarrow x=19.31\ ft

Therefore, the surfer is at a distance of 19.31 ft from the base of the tower.

7 0
3 years ago
Does anybody know the answers to these? will mark brainliest!
jeyben [28]

Answer:

1.

Tan 45=√2/n

n=√2

again

sin 45=√2/m

m=2

answer:<u> </u><u>m</u><u>=</u><u>2</u><u>,</u><u>n</u><u>=</u><u>√</u><u>2</u>

<u>2</u><u>.</u>

sin 45=x/3

x=3/√2=3√2/2

y=3√2/2

<u>a</u><u>n</u><u>s</u><u>:</u><u>x</u><u>=</u><u>3√2/2</u><u>,</u><u>y</u><u>=</u><u>3√2/</u><u>3</u>

<u>3</u><u>.</u>

sin 45=a/4

a=4/√2

b=4/√2

ans:<u>a</u><u>=</u><u>4</u><u>/</u><u>√</u><u>2</u><u>,</u><u>b</u><u>=</u><u>4</u><u>/</u><u>√</u><u>2</u>

4.

b=4 base sides of isosceles triangle

sin 45=4/a

a=4√2

ans:<u>a</u><u>=</u><u>4</u><u>√</u><u>2</u><u> </u><u>and</u><u> </u><u>b</u><u>=</u><u>4</u>

5 0
3 years ago
4) There are 4 marbles and 3 cubes in a board game. The marbles are black, blue, yellow, and red. The cubes are numbered 1, 2, a
krek1111 [17]

Answer:

<u>Here is the sample space, its size is 4*3 = 12:</u>

  • Black 1
  • Black 2
  • Black 3
  • Blue 1
  • Blue 2
  • Blue 3
  • Yellow 1
  • Yellow 2
  • Yellow 3
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3 0
3 years ago
Read 2 more answers
The Ohio Department of Agriculture tested 203 fuel samples across the state
Rus_ich [418]

Answer:

\hat p = \frac{14}{105}= 0.133

And that represent the proportion of failures.

The confidence interval for the mean is given by the following formula:  

\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}

If we replace the values obtained we got:

0.133 - 2.58\sqrt{\frac{0.133(1-0.133)}{105}}=0.0475

0.133 + 2.58\sqrt{\frac{0.133(1-0.133)}{105}}=0.2185

The 99% confidence interval would be given by (0.0475;0.2185)

Step-by-step explanation:

Previous concept

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The population proportion have the following distribution

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})

Solution to the problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 99% of confidence, our significance level would be given by \alpha=1-0.99=0.01 and \alpha/2 =0.005. And the critical value would be given by:

z_{\alpha/2}=-2.58, z_{1-\alpha/2}=2.58

The proportion estimated would be:

\hat p = \frac{14}{105}= 0.133

And that represent the proportion of failures.

The confidence interval for the mean is given by the following formula:  

\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}

If we replace the values obtained we got:

0.133 - 2.58\sqrt{\frac{0.133(1-0.133)}{105}}=0.0475

0.133 + 2.58\sqrt{\frac{0.133(1-0.133)}{105}}=0.2185

The 99% confidence interval would be given by (0.0475;0.2185)

3 0
3 years ago
Read 2 more answers
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