Oh wow mine is due in half an hour too
R(9p^2+73p+70)
r(9p+10)(p+7)
The volume of the cone by definition is given by:
V = (pi * r ^ 2 * h) / 3
Where,
h: height
r: radio
Substituting the values we have:
V = (pi * (9/2) ^ 2 * (16)) / 3
V = 339.2920066 in ^ 3
Rounding:
V = 339.3 in ^ 3
Answer:
the volume of the cone is:
V = 339.3 in ^ 3
Answer:
a = 9.849
b = 20.25
c = 491.03
Step-by-step explanation:
By using Pythagoras theorem in the right triangle BDC,
(Hypotenuse)² = (Leg 1)² + (Leg 2)²
BC² = BD² + DC²
a² = 9² + 4²
a = 
a = 
a = 9.8489
a ≈ 9.849 units
By mean proportional theorem,

AD × DC = BD²
b × 4 = 9²
b = 
b = 20.25 units
BY Pythagoras theorem in ΔADB,
AB² = AD² + BD²
c² = b² + 9²
c² = (20.25)² + 9²
c² = 410.0625 + 81
c = 491.0625
c = 491. 063 units
Hope this will help you 2(-15)-1=-31