I am not sure exactly how to do it but based on my knowledge, I think the answer would be 1/38
Answer:

Step-by-step explanation:
For a standard normal distribution of mean
and 
the statistic 
In this problem we look for the value of X that is 2 standard deviations above the mean.
If there are two standard deviations above the mean, then, in the standard normal distribution, the statistic
.
Then, we clear X.

Where:

Answer: 151
Step-by-step explanation:
if prior population proportion is unknown , then the formula is used to find the sample size :

, where
= Two tailed critical value for significance level of 
E = Margin of error.
Given : margin of error = 8%= .08
For 95% confidence level , two tailed critical value = 1.96
Now, the required sample size :

Hence, the size of the sample needed = 151.
Answer: -30b^2+76b+80
Explanation:
Multiply the second parenthesis by each term from the first parenthesis:
3b•2(-2•2+b+10)+4b•(-2b•2+b+10)+8(-2b•2+b+10)
Then distribute 3b•2 through the parenthesis
-24b^2+6b^2+60b+4b•(-2b•2+b+10)+8(-2b•2+b+10)
Then collect like terms
-30b^2+60b+40b-32b+8b+80
Collect like terms=
-30b+76b+80