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Helga [31]
3 years ago
9

Four rectangles are shown in the diagram. For which pair of rectangles is the ratio of the side lengths 1:3?

Mathematics
1 answer:
kondor19780726 [428]3 years ago
5 0
The answer is B. because it is 6:9 which simplifies down to 1:3
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PLEASE HELLPPPPPPPPPPPPPPPPPPPPPPPPPPP
suter [353]

Answer:

a) 33

B) 65?

C) 60?

D) Becuase its the same shape just smaller.

E) 14, its cut in half

Step-by-step explanation:

be careful if you use these, its been a while since I geometry.

7 0
3 years ago
Pls help this is pretty urgent
laiz [17]

Answer:

(a)  See below.

(b)  x = 0 or x = 1

(c)  x = 0 removable, x = 1 non-removable

Step-by-step explanation:

Given rational function:

f(x)=\dfrac{\ln |x-1|}{x}

<u>Part (a)</u>

Substitute x = 2 into the given rational function:

\begin{aligned}\implies f(2) & =\dfrac{\ln |2-1|}{2}\\\\ & =\dfrac{\ln 1}{2}\\\\ & =\dfrac{0}{2}\\\\ & =0\end{aligned}

Therefore, as the function is defined at x = 2, the function is continuous at x = 2.

<u>Part (b)</u>

Given interval:  [-2, 2]

Logs of negative numbers or zero are undefined.  As the numerator is the natural log of an <u>absolute value</u>, the numerator is undefined when:

|x - 1| = 0 ⇒ x = 1.  

A rational function is undefined when the denominator is equal to zero, so the function f(x) is undefined when x = 0.

So the function is discontinuous at x = 0 or x = 1 on the interval [-2, 2].

<u>Part (c)</u>

x = 1 is a <u>vertical asymptote</u>.  As the function exists on both sides of this vertical asymptote, it is an <u>infinite discontinuity</u>.  Since the function doesn't approach a particular finite value, the limit does not exist.  Therefore, x = 1 is a non-removable discontinuity.

A <u>hole</u> exists on the graph of a rational function at any input value that causes both the numerator and denominator of the function to be equal.

\implies f(0)=\dfrac{\ln |0-1|}{0}=\dfrac{\ln 1}{0}=\dfrac{0}{0}

Therefore, there is a hole at x = 0.

The removable discontinuity of a function occurs at a point where the graph of a function has a hole in it.   Therefore, x = 0 is a removable discontinuity.

3 0
2 years ago
Read 2 more answers
A rectangular aquarium has length (x+ 10), width (x + 4), and height (t + 6). Determine a simplified function that represents th
Helga [31]

Answer:

V = x³ + 20x² + 124x + 240

Step-by-step explanation:

Volume of a rectangular prism is width times length times height.

V = wlh

Given w = x+4, l = x+10, and h = x + 6:

V = (x + 4)(x + 10)(x + 6)

V = (x + 4)(x² + 16x + 60)

V = x²(x + 4) + 16x(x + 4) + 60(x + 4)

V = x³ + 4x² + 16x² + 64x + 60x + 240

V = x³ + 20x² + 124x + 240

7 0
3 years ago
Simplify expression <br> 4(7x+5y)
Margarita [4]
28x + 20y I think is the answer
6 0
4 years ago
Read 2 more answers
Find the area of the regular polygon. Round your answer to the<br> nearest tenth if necessary.
Alina [70]

Answer:

156.8

Step-by-step explanation:

You can break up this hexagon into 6 triangles of size

7.8 (the base) and 6.7 (the height)

Thus, you can find the area of 1 and multiply it by 6 to get the answer of 156.78 and to round it is 156.8

Please help me, i need branliest answers. I hope u help me:)

8 0
4 years ago
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