The answer is 3, subtract or add like terms
Answer:
3 < x < 17
Step-by-step explanation:
Given 2 sides then the possible range of the third side x is
difference of 2 sides < x < sum of 2 sides , that is
10 - 7 < x < 10 + 7
3 < x < 17
Disclaimer- this is all assuming that "semi monthly" means twice a month. if it doesn't, ignore this answer
A- if semi monthly is half a month, then 4 times 2 is 8, and 8 times 12 is 96,000.
B- If there are 4 weeks in a month and 4000$ accounts for half of that pay, then the weekly pay is 2000, making the bi-weekly pay 1000.
C- The monthly pay is 8,000$ because 4,000 x 2 is 8,000
D- The weekly pay is 2,000$ because the monthly pay is 8,000$ and there are 4 weeks in a month
E- I do not know the hours at this job and therefore cannot answer this
Answer:
The midpoint of the segment with endpoints at the midpoints of s1 and s2 is (4,5).
Step-by-step explanation:
Midpoint of a segment:
The coordinates of the midpoint of a segment are the mean of the coordinates of the endpoints of the segment.
Midpoint of s1:
Using the endpoints given in the exercise.
![x = \frac{3 + \sqrt{2} + 4}{2} = \frac{7 + \sqrt{2}}{2}](https://tex.z-dn.net/?f=x%20%3D%20%5Cfrac%7B3%20%2B%20%5Csqrt%7B2%7D%20%2B%204%7D%7B2%7D%20%3D%20%5Cfrac%7B7%20%2B%20%5Csqrt%7B2%7D%7D%7B2%7D)
![y = \frac{5 + 7}{2} = \frac{12}{2} = 6](https://tex.z-dn.net/?f=y%20%3D%20%5Cfrac%7B5%20%2B%207%7D%7B2%7D%20%3D%20%5Cfrac%7B12%7D%7B2%7D%20%3D%206)
Thus:
![M_{s1} = (\frac{7 + \sqrt{2}}{2},6)](https://tex.z-dn.net/?f=M_%7Bs1%7D%20%3D%20%28%5Cfrac%7B7%20%2B%20%5Csqrt%7B2%7D%7D%7B2%7D%2C6%29)
Midpoint of s2:
![x = \frac{6 - \sqrt{2} + 3}{2} = \frac{9 - \sqrt{2}}{2}](https://tex.z-dn.net/?f=x%20%3D%20%5Cfrac%7B6%20-%20%5Csqrt%7B2%7D%20%2B%203%7D%7B2%7D%20%3D%20%5Cfrac%7B9%20-%20%5Csqrt%7B2%7D%7D%7B2%7D)
![y = \frac{3 + 5}{2} = \frac{8}{2} = 4](https://tex.z-dn.net/?f=y%20%3D%20%5Cfrac%7B3%20%2B%205%7D%7B2%7D%20%3D%20%5Cfrac%7B8%7D%7B2%7D%20%3D%204)
Thus:
![M_{s2} = (\frac{9 - \sqrt{2}}{2}, 4)](https://tex.z-dn.net/?f=M_%7Bs2%7D%20%3D%20%28%5Cfrac%7B9%20-%20%5Csqrt%7B2%7D%7D%7B2%7D%2C%204%29)
Find the midpoint of the segment with endpoints at the midpoints of s1 and s2.
Now the midpoint of the segment with endpoints
and
. So
![x = \frac{\frac{7 + \sqrt{2}}{2} + \frac{9 - \sqrt{2}}{2}}{2} = \frac{16}{4} = 4](https://tex.z-dn.net/?f=x%20%3D%20%5Cfrac%7B%5Cfrac%7B7%20%2B%20%5Csqrt%7B2%7D%7D%7B2%7D%20%2B%20%5Cfrac%7B9%20-%20%5Csqrt%7B2%7D%7D%7B2%7D%7D%7B2%7D%20%3D%20%5Cfrac%7B16%7D%7B4%7D%20%3D%204)
![y = \frac{6 + 4}{2} = \frac{10}{2} = 5](https://tex.z-dn.net/?f=y%20%3D%20%5Cfrac%7B6%20%2B%204%7D%7B2%7D%20%3D%20%5Cfrac%7B10%7D%7B2%7D%20%3D%205)
The midpoint of the segment with endpoints at the midpoints of s1 and s2 is (4,5).
When you name two congruent triangles with the letters of the vertices, you keep the order of the corresponding vertices. That means, that when you say triangle GHI is congruent to JKL, the corresponding congruent angles are G = J, H = K, and I = L. regarding the sides, segment GH = segment JK, segment HI = segment KL, and segment IG = segment LJ. Then, the answer is that, of the four options,<span> the one that is not true is the option c, because as we already said the corresponding equal segment to GH is JK and not KL.</span>