Question

Help on number 1 plz I go back to school tomorrow

Answer 1

in 1/3 of the day, the glacier moves 3/4 of a meter

Multiply 3 with 1/3 to get a whole day

3 x 1/3 = 1

Multiply 3 with 3/4 of a meter too, to get the amount moved in 1 day

3 x 3/4 = 9/4

9/4, or 2 1/4 meters is your answer

hope this helps

Answer 2

You are asked for a rate in meters per day. That means you need to divide the number of meters by the number of days.

$(\dfrac{3}{4}~m) \div (\dfrac{1}{3}~day) =$

$= \dfrac{3~m}{4} \div \dfrac{1~day}{3}$

$= \dfrac{3~m}{4} \times \dfrac{3}{1~day}$

$= \dfrac{3 \times 3}{4 \times 1} ~\dfrac{m}{day}$

$= \dfrac{9}{4} \dfrac{m}{day}$

$= 2.25~\dfrac{m}{day}$