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Papessa [141]
3 years ago
13

What is the least to greatest area

Mathematics
1 answer:
dolphi86 [110]3 years ago
5 0
Least to greatest:
nevada, arizona, californa, montana, texas, alaska
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James puts $3,500 into a savings account that earns 2.5% simple interest. He does not touch that account for 3 years. What would
miskamm [114]

Given :

James puts $3,500 into a savings account that earns 2.5% simple interest.

He does not touch that account for 3 years.

To Find :

The new balance of the account be after 3 years.

Solution :

Interest on $3500 after 3 years is :

I = \dfrac{P_o\times r\times t}{100}\\\\I = \dfrac{3500\times 2.5\times 3}{100}\\\\I = \$262.5

So, new balance of the account after 3 years is $( 3500+262.5 ) = $3762.5  .

Hence, this is the required solution.

3 0
3 years ago
Monic and Rachel purchased a tv for $378. Monica paid $36 less then Rachel. How many did each person pay for the tv? Solve using
topjm [15]

Answer:

Monica paid $171 while Rachel paid $207

Step-by-step explanation:

We are told that Monic and Rachel purchased a tv for $378.

Let the amount spent by Monica be X and the amount spent by Rachel be Y.

Thus;

x + y = 378 - - - - (eq 1)

We are told that Monica paid $36 less then Rachel. Thus;

y = x + 36

Or y - x = 36 - - - (eq 2)

Add eq 1 & eq 2 together to give;

2y = 378 + 36

2y = 414

y = 414/2

y = $207

Put 207 for x in eq 1 to get;

x + 207 = 378

x = 378 - 207

x = $171

Thus;

Monica paid $171 while Rachel paid $207

8 0
2 years ago
Which measure of center​ (mean or​ median) is​ resistant?
IRISSAK [1]

The median is resident to change, it is not affected by extreme values.
5 0
3 years ago
What's the equation of the given graph?​
kozerog [31]

Answer:

y=2x

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
If cos theta= -8/17 and theta is in quadrant 3, what is cos2 theta and tan2 theta
Karo-lina-s [1.5K]
\bf cos(\theta)=\cfrac{adjacent}{hypotenuse}\qquad  
\begin{array}{llll}
\textit{now, hypotenuse is always positive}\\
\textit{since it's just the radius}
\end{array}
\\\\\\
thus\qquad cos(\theta)=\cfrac{-8}{17}\cfrac{\leftarrow adjacent=a}{\leftarrow  hypotenuse=c}

since the hypotenuse is just the radius unit, is never negative, so the - in front of 8/17 is likely the numerator's, or the adjacent's side

now, let us use the pythagorean theorem, to find the opposite side, or "b"

\bf c^2=a^2+b^2\implies \pm\sqrt{c^2-a^2}=b\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite
\end{cases}
\\\\\\
\pm\sqrt{17^2-(-8)^2}=b\implies \pm\sqrt{225}=b\implies \pm 15=b

so... which is it then? +15 or -15? since the root gives us both, well
angle θ, we know is on the 3rd quadrant, on the 3rd quadrant, both, the adjacent(x) and the opposite(y) sides are negative, that means,  -15 = b

so, now we know, a = -8, b = -15, and c = 17
let us plug those fellows in the double-angle identities then

\bf \textit{Double Angle Identities}
\\ \quad \\
sin(2\theta)=2sin(\theta)cos(\theta)
\\ \quad \\
cos(2\theta)=
\begin{cases}
cos^2(\theta)-sin^2(\theta)\\
\boxed{1-2sin^2(\theta)}\\
2cos^2(\theta)-1
\end{cases}
\\ \quad \\
tan(2\theta)=\cfrac{2tan(\theta)}{1-tan^2(\theta)}\\\\
-----------------------------\\\\
cos(2\theta)=1-2sin^2(\theta)\implies cos(2\theta)=1-2\left( \cfrac{-15}{17} \right)^2
\\\\\\
cos(2\theta)=1-\cfrac{450}{289}\implies cos(2\theta)=-\cfrac{161}{289}




\bf tan(2\theta)=\cfrac{2tan(\theta)}{1-tan^2(\theta)}\implies tan(2\theta)=\cfrac{2\left( \frac{-15}{-8} \right)}{1-\left( \frac{-15}{-8} \right)^2}
\\\\\\
tan(2\theta)=\cfrac{\frac{15}{4}}{1-\frac{225}{64}}\implies tan(2\theta)=\cfrac{\frac{15}{4}}{-\frac{161}{64}}
\\\\\\
tan(2\theta)=\cfrac{15}{4}\cdot \cfrac{-64}{161}\implies tan(2\theta)=-\cfrac{240}{161}
6 0
3 years ago
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