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drek231 [11]
3 years ago
9

What is the first step in solving the quadratic equation -5x2+8=133

Mathematics
1 answer:
astraxan [27]3 years ago
4 0
I don’t think you can solve by using quadratic equation

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IF YOU GET IT RIGHT ILL MARK AS BRANLIST!!! which of the following graphs show a proportional relationship?
nexus9112 [7]

Answer:

Its a and b if you can click them both but its not c

3 0
3 years ago
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the marks in an examination for a Physics paper have normal distribution with mean μ and variance σ2 . 10% of the students obtai
Blababa [14]

Let X be the random variable for the number of marks a given student receives on the exam.

10% of students obtain more than 75 marks, so

P(X>75)=P\left(\dfrac{X-\mu}\sigma>\dfrac{75-\mu}\sigma\right)=P(Z>z_1)=0.10

where Z follows a standard normal distribution. The critical value for an upper-tail probability of 10% is

P(Z>z_1)=1-F_Z(z_1)=0.10\implies z_1=F_Z^{-1}(0.90)

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z_1=F_Z^{-1}(0.90)\approx1.2816

Similarly, because 20% of students obtain less than 40 marks, we have

P(X

so that

P(Z

Then \mu,\sigma are such that

\dfrac{75-\mu}\sigma\approx1.2816\implies75\approx\mu+1.2816\sigma

\dfrac{40-\mu}\sigma\approx-0.8416\implies40\approx\mu-0.8416\sigma

and we find

\mu\approx53.8739,\sigma\approx16.4848

3 0
3 years ago
Does this set of ordered pairs represent a function? (-1,5)(0,-3)(2,7)(4,0)(7,5)
ruslelena [56]

Answer:

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Step-by-step explanation:

You cant have 2 y values

6 0
2 years ago
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uysha [10]

Answer: 0.38

Step-by-step explanation:

Since the variable x is represented by a standard normal distribution, the probability of x > 0.3 will be calculated thus:

P(x > 0.3)

Then, we will use a standard normal table

P(z > 0.3)

= 1 - p(z < 0.3)

= 1 - 0.62

= 0.38

Therefore, p(x > 0.3) = 0.38

The probability of x > 0.3 is 0.38.

5 0
2 years ago
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