Answer:
w > 0
Step-by-step explanation:
-5 > -5 - 8w
+5 +5
--------------------
0 > -8w
/-8 /-8
--------------------
0 > w
w > 0
There are 2 options to solve that.
1. The first one is by derivatives.
f(x)=x^2+12x+36
f'(x)=2x+12
then you solve that for f'(x)=0
0=2x+12
x=(-6)
you have x so for (-6) solve the first equation, then you find y
y=(-6)^2+12*(-6)+36=(-72)
so the vertex is (-6, -72)
2. The second option is to solve that by equations:
for x we have:
x=(-b)/2a
for that task we have
b=12
a=1
x=(-12)/2=(-6)
you have x so put x into the main equation
y=(-6)^2+12*(-6)+36=(-72)
and we have the same solution: vertex is (-6, -72)
For next task, I will use the second option:
y=x^2-6x
x=(-b)/2a
for that task we have
b=(-6)
a=1
x=(6)/2=3
you have x so put x into the main equation
y=3^2+(-6)*3=(--9)
and we have the same solution: vertex is (3, -9)
Answer:
Step-by-step explanation if u know how to use standered algorithim just divide the same way you divided p.s the answer is 11.2485939258 .
Answer:
nonlinear
Step-by-step explanation:
The degree of x in the equation is not 0 or 1, so the function is nonlinear.
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<em>Additional comment</em>
Your function graphs as a parabola, not a straight line. A function is only linear if its graph is a straight (non-vertical) line.
