The quantity which is equivalent to the product of the absolute index of refraction of water and the speed of light in water system is the speed of light in vacuum.

<h3>What is the speed of light?</h3>

Speed of light is the rate of speed though the light travels. To find the speed of light in any medium, the following formula is used.

$v=\dfrac{c}{n}$

Here, (n) is the index of reaction and (c) is the speed of light in the vacuum. The speed of light in the vacuum is almost equal to the 3.0×10⁸ m/s.

Now the quantity which is equivalent to the product of the absolute index of refraction of water and the speed of light in water has to be find out.

The above formula can be written as,

$v=\dfrac{c}{n}\\vn=c\\c=vn$

Here, the product of index of refraction and speed of light is equal to the speed of light in vacuum. This will be true for water as well.

Thus, the quantity which is equivalent to the product of the absolute index of refraction of water and the speed of light in water system is the speed of light in vacuum.

Learn more about the speed of light here;

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3 0

2 years ago

Complete and balance the following equation:

sertanlavr [38]

You need to add the last substance to the products side(the right sode of the arrow). You have hydrogen and oxygen - water.

You get: BrO3 + N2H4 -> Br2 + N2 + H2O

# of Br: 1x1 = 1 # of Br: 2x1 = 2
O: 3x1 = 3 O: 1x1 = 1
N: 2x1 = 2 B N: 2x1 = 2
H: 4x1 = 4. H: 2x1 = 2

Br:
Multiply the reactant (left) side by 2 to balance.

O:
You've just multiplied the reactant oxygen by 2 so now the reactant side equals 6. Multiply the product (right) side by six as well.

H:
The product side is now equal to 12. Multiply the reactant side by 3 to balance.

N:
Now you have to balance N because the reactant side has been risen. So multiply the product side by three as well.

You end up with the complete and balanced equation:

2BrO3 + 3N2H4 -> Br2 + 3N2 + 6H2O

4 0

4 years ago

What is the volume of 14.0 g of nitrogen gas, N2, at a pressure of 2.00 atm and temperature of 27.0 degree celsius

Lelu [443]

P = 2.00 atm = 2026.50hPa
T = 27°C = 300K
m = 14.0g |
Mr = 28g/mol | n = m/M = 14g/28g/mol = 0,5mol
R = 83.1 [hPa*L]/[mol*K]

pV = nRT

nRT 0,5mol * 83.1[hPa*L]/[mol*K] * 300K
V = ---------- = ----------------------------------------------------------- = <u>6.15L</u>
p 2026.5hPa

Answer B.

3 0

3 years ago

How do you determine the theoretical number of electrons in an energy level?

Makovka662 [10]

I'm pretty sure the formula is 2n(/\) 2

3 0

3 years ago