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Scrat [10]
3 years ago
6

What is the volume of 14.0 g of nitrogen gas, N2, at a pressure of 2.00 atm and temperature of 27.0 degree celsius

Chemistry
1 answer:
Lelu [443]3 years ago
3 0
P = 2.00 atm = 2026.50hPa
T = 27°C = 300K
m = 14.0g              |
Mr = 28g/mol         |      n = m/M = 14g/28g/mol = 0,5mol
R = 83.1 [hPa*L]/[mol*K]

pV = nRT

        nRT        0,5mol * 83.1[hPa*L]/[mol*K] * 300K
V = ---------- = ----------------------------------------------------------- = <u>6.15L</u>
           p                           2026.5hPa

Answer B.
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A sample of gas has a pressure of 100.0 KPa and 25C. Calculate the pressure if the temperature is changed to 125C while the volu
atroni [7]

Answer:

133.56kPa

Explanation:

Applying Pressure Law,

P/T = P'/T'....................... Equation 1

Where P = Initial pressure, T = Initial Temperature, P' = Final pressure, T' = Final Temperature.

From the question, we were asked to calculate P'

There, we make P' the subject of the equation

P' = PT'/T...................... Equation 2

Given: P = 100kPa, T = 25°C = (273+25) = 298K, T' = 125°C = (273+1250K = 398 K

Substitute these values into equation 2

P' = (100×398)/298

P' = 133.56kPa

Hence the pressure is 133.56kPa

6 0
3 years ago
The following information is given for ether, C2H5OC2H5, at 1atm: boiling point = 34.6 °C Hvap(34.6 °C) = 26.5 kJ/mol specific h
Likurg_2 [28]

Answer:

The heat is  H= -8.044KJ

Explanation:

From the question we are told that

   The pressure is  P = 1 \ atm

    The boiling point is  B_P  = 34^oC

     The heat of vaporization at 34°C is  = 26.5 kJ/mol

       The specific heat of the liquid is c_p = 2.32 J/g^oC

      The  mass is  m = 22.5g

  The no of moles of the sample of C_2 H_5OC_2H_5  is given as

               No \ mole (n)  = \frac{Mass \ of  \ sample }{Molar \ mass }

    The  Molar mass for C_2 H_5OC_2H_5  is a value = = 74.12 g/mol

Substituting the value into the above equation

          n  = \frac{22.5}{74.12}

                           = 0.30356 \ mol

      The heat H is mathematically as

                H  =- nH_{vap}

The negative sign show that the heat is for condensing

            H = 0.30356 * 26.5 *10^{3} J/mol

                H= -8.044KJ

                   

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