Answer:
20L is the new volume
Explanation:
In this case, moles and T° from the gas remain constant. This is the formula we must apply, to solve this:
P₁ . V₁ = P₂ . V₂
5 atm . 10 L = P₂ . 2.5L
P₂ = (5 atm . 10 L) / 2.5L →20L
Answer:
answer = 22.5m
Explanation:
using

s= (0²-21²)/2(-9.8)
s= -441/19.6
s= 22.5m
do consider marking as Brainliest if this helped!!
Molarity of concentrated nitric acid = 15.9 M
Volume of the stock solution to be prepared = 500.0 mL
Concentration of the stock that is to be prepared = 0.750 M
Calculating moles from molarity and volume of stock:

Calculating volume of concentrated nitric acid to be taken for the preparation of stock solution:

Converting L to mL:
= 23.6 mL
Volume of distilled water to be added to 23.6 mL of 15.9 M nitric acid to get the given concentration = 5000.0mL-23.6mL=976.4 mL
Therefore, 976.4 mL distilled water is to be added to 23.6 mL of 15.9 M nitric acid solution to prepare 500.0 mL of 0.750M nitric acid.
C) It contains the same number of electrons and protons.