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slamgirl [31]
3 years ago
6

Heights​ (cm) and weights​ (kg) are measured for 100 randomly selected adult​ males, and range from heights of 133 to 193 cm and

weights of 40 to 150 kg. Let the predictor variable x be the first variable given. The 100 paired measurements yield x overbarequals167.90 ​cm, y overbarequals81.47 ​kg, requals0.228​, ​P-valueequals0.023​, and ModifyingAbove y with caretequalsnegative 105plus1.13x. Find the best predicted value of ModifyingAbove y with caret ​(weight) given an adult male who is 172 cm tall. Use a 0.05 significance level. The best predicted value of ModifyingAbove y with caret for an adult male who is 172 cm tall is nothing kg. ​(Round to two decimal places as​ needed.)
Mathematics
1 answer:
yawa3891 [41]3 years ago
5 0

Answer:

The weight of an adult male who is 172 cm tall is 89.36 kg.

Step-by-step explanation:

The regression equation representing the relationship between height and weight of a person is:

\hat y=-105+1.13x

Here

<em>y</em> = weight of a person

<em>x</em> = height of a person

The information provided is:

\bar x=167.90\ cm\\\bar y=81.47\ kg\\r (X, Y) = 0.228\\p-value=0.023\\\alpha =0.05

The hypothesis to test the significance of the correlation between height and weight is:

<em>H₀</em>: There is no relationship between the height and weight, i.e. <em>ρ</em> = 0.

<em>Hₐ</em>: There is a relationship between the height and weight, i.e. <em>ρ </em>≠ 0.

Decision rule:

If the <em>p</em>-value of the test is less than the significance level, then the null hypothesis will be rejected and vice-versa.

According to information provided:

<em>p</em>-value = 0.023 < <em>α</em> = 0.05

The null hypothesis was rejected at 5% level of significance.

Thus, concluding that there is a relationship between the height and weight.

Compute the weight of an adult male with height, <em>x</em> = 172 cm as follows:

\hat y=-105+1.13x

  =-105+(1.13\times 172)\\=-105+194.36\\=89.36

Thus, the weight of an adult male who is 172 cm tall is 89.36 kg.

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<h2>~<u>Solution</u> :-</h2>

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6(2)

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