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professor190 [17]
3 years ago
6

What is the measure of UVW in the triangle shown? A. 140° B. 50° C. 60° D. 10°​

Mathematics
1 answer:
Vilka [71]3 years ago
4 0

Answer:

b

Step-by-step explanation:

40 + 90 =130

180-130=50

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Create a graph that has the following intercepts. Make sure to label each of the intercepts on
SCORPION-xisa [38]

Answer:

  see below for the graph

Step-by-step explanation:

The desired graph has two y-intercepts and one x-intercept. It is not the graph of a function.

Here's one way to get there.

__

Start with the parent function y = |x| and scale it down so that it has a y-intercept of -1 and x-intercepts at ±1.

Now, it is ...

  f(x) = |x| -1

We want to scale this vertically by a factor of -5. this puts the y-intercept at +5 and leaves the x-intercepts at ±1.

Horizontally, we want to scale the function by an expansion factor of 3. The transformed function g(x) will be ...

  g(x) = -5f(x/3) = -5(|x/3| -1) = -5/3|x| +5

This function has two x-intercepts at ±3 and one y-intercept at y=5. By swapping the x- and y-variables, we can get an equation for the graph you want:

  x = -(5/3)|y| +5

______

<em>Comment on this answer</em>

Since there are no requirements on the graph other than it have the listed intercepts, you can draw it free-hand through the intercept points. It need not be describable by an equation.

7 0
3 years ago
What is the greatest common factor of 44c^5, 22c^3 and 11c^4
Alexxandr [17]

\text{ GCF of } 44c^5, 22c^3 , 11c^4 \text{ is } 11c^3

<em><u>Solution:</u></em>

Given that, we have to find the greatest common factor of 44c^5, 22c^3 , 11c^4

The greatest number that is a factor of two (or more) other numbers.

When we find all the factors of two or more numbers, and some factors are the same ("common"), then the largest of those common factors is the Greatest Common Factor

\underline{\text{ GCF of } 44c^5, 22c^3 , 11c^4 :}

First find the GCF of numbers and then find the GCF of variables and then multiply them together

<em><u>Step 1: GCF of 44, 22 and 11</u></em>

The factors of 11 are: 1, 11

The factors of 22 are: 1, 2, 11, 22

The factors of 44 are: 1, 2, 4, 11, 22, 44

11 is the greatest factor that is common in above three list

Then the greatest common factor is 11

\text{ Step 2: GCF of }c^5, c^3 , c^4

c^5 = c^3 \times c^2\\\\c^3 = c^2 \times c^1 \text{ or } c^3\\\\c^4 = c^3 \times c^1

Thus the greatest common factor is c^3

Step 3: Multiply the GCF of 44, 22, 11 and GCF of c^5, c^3 , c^4

\text{ GCF of } 44c^5, 22c^3 , 11c^4 = 11 \times c^3 = 11c^3

Thus \text{ GCF of } 44c^5, 22c^3 , 11c^4 \text{ is } 11c^3

8 0
3 years ago
The bakery sells 8 doughnuts for every 3 bagels sold. If the bakery sells 9 bagels in a day, how many doughnuts are sold?
Lunna [17]

Answer:

24. here is the explanation

if 8 donuts are sold for each 3 bagels sold and the bakery sold 9 in a day. 3x3x3 = 9. and if 8 are for every 3... just multiply 8 x 3 is 24.

Step-by-step explanation:

3 0
4 years ago
PLS PLS PLS PLS HELP!
NikAS [45]

Answer:

-10

Step-by-step explanation:

(-6)+(-4)

3 0
3 years ago
The editor of a textbook publishing company is deciding whether to publish a proposed textbook. Information on previous textbook
kogti [31]

Answer:

34.86% probability that it will be huge​ success

Step-by-step explanation:

Bayes Theorem:

Two events, A and B.

P(B|A) = \frac{P(B)*P(A|B)}{P(A)}

In which P(B|A) is the probability of B happening when A has happened and P(A|B) is the probability of A happening when B has happened.

In this question:

Event A: Receiving a favorable review.

Event B: Being a huge success.

Information on previous textbooks published show that 20 % are huge​ successes

This means that P(B) = 0.2

99 % of the huge successes received favorable​ reviews

This means that P(A|B) = 0.99

Probability of receiving a favorable review:

20% are huge​ successes. Of those, 99% receive favorable reviews.

30% are modest​ successes. Of those, 70% receive favorable reviews.

30% break​ even. Of those, 40% receive favorable reviews.

20% are losers. Of those, 20% receive favorable reviews.

Then

P(A) = 0.2*0.99 + 0.3*0.7 + 0.3*0.4 + 0.2*0.2 = 0.568

Finally

P(B|A) = \frac{P(B)*P(A|B)}{P(A)} = \frac{0.2*0.99}{0.568} = 0.3486

34.86% probability that it will be huge​ success

4 0
3 years ago
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