Answer:
y= -7
Step-by-step explanation:
First, you replace the x with zero.
y=4*0-7
Then, you simplify the right side of the equation.
y=0-7
y= -7
<u>Given</u><u> </u><u>info:</u><u>-</u>If the radius of a right circular cylinder is doubled and height becomes 1/4 of the original height.
Find the ratio of the Curved Surface Areas of the new cylinder to that of the original cylinder ?
<u>Explanation</u><u>:</u><u>-</u>
Let the radius of the right circular cylinder be r units
Let the radius of the right circular cylinder be h units
Curved Surface Area of the original right circular cylinder = 2πrh sq.units ----(i)
If the radius of the right circular cylinder is doubled then the radius of the new cylinder = 2r units
The height of the new right circular cylinder
= (1/4)×h units
⇛ h/4 units
Curved Surface Area of the new cylinder
= 2π(2r)(h/4) sq.units
⇛ 4πrh/4 sq.units
⇛ πrh sq.units --------(ii)
The ratio of the Curved Surface Areas of the new cylinder to that of the original cylinder
⇛ πrh : 2πrh
⇛ πrh / 2πrh
⇛ 1/2
⇛ 1:2
Therefore the ratio = 1:2
The ratio of the Curved Surface Areas of the new cylinder to that of the original cylinder is 1:2
Answer: Your answer is A,C, and D
Step-by-step explanation:
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The solutions to the system of equations are (-2,-6) and (4,6)
<h3>How to determine the system of equations?</h3>
We have:
-2x + y = -2

Next, we plot the graph of both functions.
From the attached graph, the equations intersect at (-2,-6) and (4,6)
Hence, the solutions to the system of equations are (-2,-6) and (4,6)
Read more about system of equations at:
brainly.com/question/21405634
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Answer:
∠ B ≈ 66.42°
Step-by-step explanation:
Using the cosine ratio in the right triangle
cos B =
=
=
, thus
B =
(
) ≈ 66.42° ( to the nearest hundredth )