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3 years ago

Which pair of angles are corresponding?

1 answer:

7 0

Corresponding angles are in the same position. For example: on the left above the line, on the left below the line, on the right above the line, on the right below the line

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Oakdale Middle School received 240 contributions for its bake sale. Of 30% of the contributions were pies, how many pies did the

tekilochka [14]

Answer:

it is 72...............

Step-by-step explanation:

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3 years ago

jane and eric decide to drive to kansas city, as they leave home in columbia, they notice the car odometer reads 22,745 miles. W

Ksju [112]

118 miles hope it hleps

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3 years ago

Determine the equation of the line passing through the points (4,-1) and (-2,-4)

jenyasd209 [6]

Answer:

y = 1/2x - 3

Step-by-step explanation:

the slope:

$m=\frac{-4-(-1)}{-2-4} =\frac{-4+1}{-6} =\frac{-3}{-6} =\frac{3}{6} =\frac{1}{2}$

the equation:

with the point (4, -1)

$y-(-1)=\frac{1}{2} (x-4)$

$y+1=\frac{1}{2}x-2$

$y=\frac{1}{2} x-2-1$

$y=\frac{1}{2} x-3$

I hope this help you

8 0

2 years ago

Pleaseee helpppp answer correctly !!!!!!!!!!!!!!!! Will mark Brianliest !!!!!!!!!!!!!!!!!

Anit [1.1K]

Answer:

540°

General Formulas and Concepts:

Math

Counting

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Geometry

Sum of Angles: 180(n - 2)°

Step-by-step explanation:

Step 1: Define

We are given a 5-sided polygon (irregular pentagon)

n = 5

Step 2: Find Sum

Substitute in n [Sum of Angles]: 180(5 - 2)°
(Parenthesis) Subtract: 180(3)°
Multiply: 540°

5 0

2 years ago

Read 2 more answers

What Val are restricted from the domain of

djverab [1.8K]

Given:

The given expression is $\frac{\left(4 x^{2}-4 x+1\right)}{(2 x-1)^{2}}$

We need to determine the values for which the domain is restricted.

Restricted values:

Let us determine the values restricted from the domain.

To determine the restricted values from the domain, let us set the denominator the function not equal to zero.

Thus, we have;

$(2x-1)^2\neq 0$

Taking square root on both sides, we get;

$2x-1\neq 0$

$2x\neq 1$

$x\neq \frac{1}{2}$

Thus, the restricted value from the domain is $x\neq \frac{1}{2}$

Hence, Option A is the correct answer.

7 0

3 years ago