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3 years ago

Which pair of angles are corresponding?

1 answer:

7 0

Corresponding angles are in the same position. For example: on the left above the line, on the left below the line, on the right above the line, on the right below the line

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Math questions, pls help me and ill reward <3 : )

EastWind [94]

Answer:

X = 6

Step-by-step explanation:

See Attachment

5 0

3 years ago

The U.S. Federal Income Tax is a progressive tax, which means that higher incomes are taxed at higher percent rates.

Kobotan [32]

Answer:

needd points

Step-by-step explanation:

thx

5 0

2 years ago

Find the value of x that makes m ∥ n.

arsen [322]

Answer:

x = 40

Step-by-step explanation:

In order for m and n to be parallel, the corresponding angles need to be equal. Therefore we get the equation:

3x = 120

Divide both sides by 3 to get:

x = 40

6 0

3 years ago

Suppose a tank contains 400 gallons of salt water. If pure water flows into the tank at the rate of 7 gallons per minute and the

Strike441 [17]

Answer:

Step-by-step explanation:

This is a differential equation problem most easily solved with an exponential decay equation of the form

$y=Ce^{kt}$ . We know that the initial amount of salt in the tank is 28 pounds, so

C = 28. Now we just need to find k.

The concentration of salt changes as the pure water flows in and the salt water flows out. So the change in concentration, where y is the concentration of salt in the tank, is $\frac{dy}{dt}$ . Thus, the change in the concentration of salt is found in

$\frac{dy}{dt}=$ inflow of salt - outflow of salt

Pure water, what is flowing into the tank, has no salt in it at all; and since we don't know how much salt is leaving (our unknown, basically), the outflow at 3 gal/min is 3 times the amount of salt leaving out of the 400 gallons of salt water at time t:

$3(\frac{y}{400})$

Therefore,

$\frac{dy}{dt}=0-3(\frac{y}{400})$ or just

$\frac{dy}{dt}=-\frac{3y}{400}$ and in terms of time,

$-\frac{3t}{400}$

Thus, our equation is

$y=28e^{-\frac{3t}{400}$ and filling in 16 for the number of minutes in t:

y = 24.834 pounds of salt

6 0

2 years ago

If 1200 cm2 of material is available to make a box with a square base and an open top, find the largest possible volume of the b

Colt1911 [192]

Answer:

The largest possible volume V is ;

V = l^2 × h

V = 20^2 × 10 = 4000cm^3

Step-by-step explanation:

Given

Volume of a box = length × breadth × height= l×b×h

In this case the box have a square base. i.e l=b

Volume V = l^2 × h

The surface area of a square box

S = 2(lb+lh+bh)

S = 2(l^2 + lh + lh) since l=b

S = 2(l^2 + 2lh)

Given that the box is open top.

S = l^2 + 4lh

And Surface Area of the box is 1200cm^2

1200 = l^2 + 4lh ....1

Making h the subject of formula

h = (1200 - l^2)/4l .....2

Volume is given as

V = l^2 × h

V = l^2 ×(1200 - l^2)/4l

V = (1200l - l^3)/4

the maximum point is at dV/dl = 0

dV/dl = (1200 - 3l^2)/4

dV/dl = (1200 - 3l^2)/4 = 0

3l^2= 1200

l^2 = 1200/3 = 400

l = √400

I = 20cm

Since,

h = (1200 - l^2)/4l

h = (1200 - 20^2)/4×20

h = (800)/80

h = 10cm

The largest possible volume V is ;

V = l^2 × h

V = 20^2 × 10 = 4000cm^3

4 0

2 years ago