Which pair of angles are corresponding?

What is the difference between these fractions?<br><br> +3/4−(+7/8)

Ket [755]

Answer:

1/8

Step-by-step explanation:

3/4 is 6/8 and 6/8 - 7/8 is 1/8

4 0

2 years ago

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What is the LCD of 2/5 and 4/11

scoundrel [369]

To find the lowest common denominator you need to know the factors of 5 and 11.
So make two lists:
5, 10, 15, 20, 25, 30, and so on.
11, 22, 33, 44, 55, 66, and so on.
Keep doing that until you find the lowest common number in the lists. The LCD will be 55.

3 0

3 years ago

I thought of a two-digit number. The unit digit of my number is a prime number, and the tens digit is four times as big as the u

sergiy2304 [10]

<h3>Answer: 82</h3>

====================================================

Explanation:

Let A be the tens digit and B be the units digit

We can write the number as AB. So if A = 9 and B = 2 for instance, then the number is AB = 92. Keep in mind I'm not multiplying A and B here.

"The unit digit is a prime" means B could be any of these values {2,3,5,7}. We only list the single digit primes. The value 1 is not prime.

Now multiply each of those items by 4

4*2 = 8

4*3 = 12

4*5 = 20

4*7 = 28

Of those results, only 4*2 = 8 leads to a single digit answer.

This must mean that A = 8 and B = 2

Therefore the number is AB = 82.

4 0

3 years ago

Based on an indication that mean daily car rental rates may be higher for Boston than for Dallas, a survey of eight car rental c

Elina [12.6K]

Answer:

$t=\frac{(47 -44)-(0)}{3\sqrt{\frac{1}{8}+\frac{1}{9}}}=2.058$

The degrees of freedom are:

$df=8+9-2=15$

And the p value would be:

$p_v =P(t_{15}>2.058) =0.0287$

Since we have a p value lower than the significance level given of 0.05 we can reject the null hypothesis and we can conclude that the true mean for car rental rates in Boston are signiﬁcantly higher than those in Dallas

Step-by-step explanation:

Data given

$n_1 =8$ represent the sample size for group Boston

$n_2 =9$ represent the sample size for group Dallas

$\bar X_1 =47$ represent the sample mean for the group Boston

$\bar X_2 =44$ represent the sample mean for the group Dallas

$s_1=3$ represent the sample standard deviation for group Boston

$s_2=3$ represent the sample standard deviation for group Dallas

We can assume that we have independent samples from two normal distributions with equal variances and that is:

$\sigma^2_1 =\sigma^2_2 =\sigma^2$

Let the subindex 1 for Boston and 2 for Dallas we want to check the following hypothesis:

Null hypothesis: $\mu_1 \leq \mu_2$

Alternative hypothesis: $\mu_1 > \mu_2$

The statistic is given by this formula:

$t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{S_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}}$

Where t follows a t student distribution with $n_1+n_2 -2$ degrees of freedom and the pooled variance $S^2_p$ is given by this formula:

$\S^2_p =\frac{(n_1-1)S^2_1 +(n_2 -1)S^2_2}{n_1 +n_2 -2}$

Replacing we got:

$\S^2_p =\frac{(8-1)(3)^2 +(9 -1)(3)^2}{8 +9 -2}=9$

And the deviation would be just the square root of the variance:

$S_p=3$

The statitsic would be:

$t=\frac{(47 -44)-(0)}{3\sqrt{\frac{1}{8}+\frac{1}{9}}}=2.058$

The degrees of freedom are:

$df=8+9-2=15$

And the p value would be:

$p_v =P(t_{15}>2.058) =0.0287$

Since we have a p value lower than the significance level given of 0.05 we can reject the null hypothesis and we can conclude that the true mean for car rental rates in Boston are signiﬁcantly higher than those in Dallas

5 0

3 years ago

Find the first six terms of the sequence.. . a1 = 6, an = 2 • an-1

irakobra [83]

6; 12, 24; 48; 96; 192

5 0

3 years ago

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