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sergejj [24]
3 years ago
10

The sand at the bottom of an hourglass has the approximate shape of a cone with a diameter of 9.85 cm and a height of 6 cm.

Mathematics
2 answers:
Svetradugi [14.3K]3 years ago
9 0

Just took the test. The answer is 160.

Hope this helped!

-Steel jelly

Murljashka [212]3 years ago
6 0
Divide the diameter by 2 to get the radius and then plug into cone volume pi*r^2*h/3 which is a bit under 160 so the answer is A
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Order the following fractions from least to greatest<br> 3/8 3/4 5/16 1/2
valentinak56 [21]

Answer:5/16 3/8 3/4 1/2

7 0
3 years ago
Read 2 more answers
For the real-valued functions f(x)=2x+1 and g(x)=sqrt(x-1), find the composition f o g and specify its domain using interval not
Anettt [7]

Answer:

fog = 2√(x-1) + 1

Domain = [1, \infty)

Step-by-step explanation:

Given the functions  f(x)=2x+1 and g(x)=sqrt(x-1), we are to find the composite function fog

fog = f(g(x))

f(g(x)) = f(√(x-1))

f(√(x+1)) means that we are to replace variable x in f(x) with the function √(x-1)

f(√(x-1)) = 2(√(x-1))+1

f(√(x+1)) = 2√(x-1) + 1

fog = 2√(x-1) + 1

<em>For the function to exist on any real valued function, then the function inside square root i.e x-1 must be greater than or equal to zero (x-1≥0)</em>

If x-1≥0

x≥0+1

x≥1

This means the range of variable x must be values of x greater than or equal to 1.

Domain = [1, \infty)

8 0
3 years ago
A stationary store has decided to accept a large shipment of ball-point pens if an inspection of 19 randomly selected pens yield
Romashka [77]

Given Information:  

Probability of shipment accepted = p = 5%

Probability of shipment not accepted = q = 95%

Total number of pens = n = 19

Required Information:  

Probability of shipment being accepted with no more than 2 defective pens = P( x ≤ 2) = ?  

Answer:

P( x ≤ 2) = 0.933

Step-by-step explanation:

The given problem can be solved using Bernoulli distribution  which is given by

P(n, x) = nCx pˣqⁿ⁻ˣ  

The probability of no more than 2 defective pens means

P( x ≤ 2) = Probability of 0 defective pen + Probability of 1 defective pen + Probability of 2 defective pens

P( x ≤ 2) = P(0) + P(1) + P(2)

For P(0) we have p = 0.05, q = 0.95, n = 19 and x = 0

P(0) = 19C0(0.05)⁰(0.95)¹⁹

P(0) = (1)(1)(0.377)

P(0) = 0.377

For P(1) we have p = 0.05, q = 0.95, n = 19 and x = 1

P(1) = 19C1(0.05)¹(0.95)¹⁸

P(1) = (19)(0.05)(0.397)

P(1) = 0.377

For P(2) we have p = 0.05, q = 0.95, n = 19 and x = 2

P(2) = 19C2(0.05)²(0.95)¹⁷

P(2) = (171)(0.0025)(0.418)

P(2) = 0.179

Therefore, the required probability is

P( x ≤ 2) = P(0) + P(1) + P(2)

P( x ≤ 2) = 0.377 + 0.377 + 0.179

P( x ≤ 2) = 0.933

P( x ≤ 2) = 93.3%

Therefore, the probability that this shipment is accepted with no more than 2 defective pens is 0.933.

8 0
3 years ago
Solve the conjunction and describe the solution set.
BaLLatris [955]
 -5 ≤ 3m + 1 < 4
- 1           - 1  - 1
 -6 ≤ 3m < 3
  3      3     3
 -2 ≤ m < 1

Solution Set: {m|-2 ≤ m < 1}, {m|m ≥ -2 and m < 1}, [-2, 1)

The answer is A.
7 0
3 years ago
(5x-6) = (2x+9) <br> 7x=3
Fofino [41]

Answer:

5

Step-by-step explanation:

5x -6 = 2x +9

5x -2x = 9 +6

3x  = 15

x = 5

4 0
3 years ago
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