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Nataly_w [17]
3 years ago
8

If four times a certain number, increased by 6 is equal to 94, what is the number?

Mathematics
2 answers:
Wewaii [24]3 years ago
7 0
X = 22. The equation is 4x + 6 = 94
elena-14-01-66 [18.8K]3 years ago
6 0

Answer: Hello mate!

"four times a certain number increased by 6 is equal to 94"

is equivalent to: 4*x + 6 = 94

where x represents the number.

Now we would want to find the value of x.

4*x + 6 = 94

4*x = 94 - 6 = 88

x = 88/4 = 22

then the value of the number x that makes the statment true is x = 22.

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What percentage of 128 is 96?
katrin [286]
So, since 100% = 128, x should equal 96, and we are trying to find x.
Multiply both sides of the equation by x.
(100/x) * x = (128/96) * x
Cancel out the x's on the left side so
100 = 1.333(x)
75 = x
96 is 75% of 128
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Angles 1 and 2 are complementary and congruent. what is the measure of angle 1? 30° 45° 50° 75°
lesantik [10]

see the attached figure to better understand the problem

we know that

1) If angle 1 and angle 2 are complementary angles

then

m∠1+m∠2=90\° ------> equation A

2) If angle 1 and angle 2 are congruent angles

then

m∠1=m∠2 ------> equation B

Substitute equation B in equation A

m∠1+(m∠1)=90\°

2m∠1=90\°

m∠1=45\°

therefore

<u>the answer is</u>

45\°

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3 years ago
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I need to divide a recipe in half that calls for 1/2 of a cup of sugar. How much sugar do I need?
ella [17]

Answer:

1/4 cup of sugar

Step-by-step explanation:

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How to write 3 9/100 as a decimal?
Artemon [7]
3 9/100 would be written as a decimal like this, 3.09. You say three and nine one hundredths. The 9 has to be in the hundredths place, so you put a 0 in front of it. And since the 3 is hole, you put it in front of the decimal point.
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Verify a(b-c)=ab-ac for a=1.6;b=1/-2;&amp; c=-5/-7​
harina [27]

Given:

a=1.6,b=\dfrac{1}{-2},c=\dfrac{-5}{-7}

To verify:

a(b-c)=ab-ac for the given values.

Solution:

We have,

a=1.6,b=\dfrac{1}{-2},c=\dfrac{-5}{-7}

We need to verify a(b-c)=ab-ac.

Taking left hand side, we get

a(b-c)=1.6\left(\dfrac{1}{-2}-\dfrac{-5}{-7}\right)

a(b-c)=1.6\left(-\dfrac{1}{2}-\dfrac{5}{7}\right)

Taking LCM, we get

a(b-c)=1.6\left(\dfrac{-7-10}{14}\right)

a(b-c)=\dfrac{16}{10}\left(\dfrac{-17}{14}\right)

a(b-c)=\dfrac{8}{5}\left(\dfrac{-17}{14}\right)

a(b-c)=-\dfrac{68}{35}\right)

Taking right hand side, we get

ab-ac=1.6\times \dfrac{1}{-2}-1.6\times \dfrac{-5}{-7}

ab-ac=-\dfrac{16}{20}-\dfrac{8}{7}

ab-ac=-\dfrac{4}{5}-\dfrac{8}{7}

Taking LCM, we get

ab-ac=\dfrac{-28-40}{35}

ab-ac=\dfrac{-68}{35}

Now,

LHS=RHS

Hence proved.

7 0
2 years ago
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