All categories

2 years ago

Which expression represents how many points each worksheet is worth?

Mathematics

2 answers:

julia-pushkina [17]2 years ago

8 0

Answer:

105 divided by 7

Step-by-step explanation:

photoshop1234 [79]2 years ago

3 0

Answer:

105 divided by 7

Step-by-step explanation:

to find out you need to divide

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I will give you a Brainly crown if it is right. Will you help me

Rufina [12.5K]

Answer:

angle b is 30 degrees

Step-by-step explanation:

a right angle is 90 degrees so you can do 90 -60 witch gets you 30 degrees

7 0

3 years ago

Which inequality describes the situation when Courtney wants to pay less than $15 for a new hat?

NeX [460]

Answer:

x<15

Step-by-step explanation:

x needs to be less than 15 since Courtney's not paying any more than that.

5 0

2 years ago

2x - 4y + 7x - 87<br> Helppp

xxTIMURxx [149]

Answer:

9x-4y-87

Step-by-step explanation:

2x-4y+7x-87

9x-4y-87

8 0

3 years ago

Read 2 more answers

4 is added to the numerator of the fraction 2/5 what number must be added to the denominator to make the fraction equivalent to

kondaur [170]

Answer: 7

Step-by-step explanation:

Hope this helps!

4 0

2 years ago

Use implicit differentiation to find an equation of the tangent line to the curve at the given point. x2/3 + y2/3 = 4 (−3 3 , 1)

vovikov84 [41]

Answer with Step-by-step explanation:

We are given that an equation of curve

$x^{\frac{2}{3}}+y^{\frac{2}{3}}=4$

We have to find the equation of tangent line to the given curve at point $(-3\sqrt3,1)$

By using implicit differentiation, differentiate w.r.t x

$\frac{2}{3}x^{-\frac{1}{3}}+\frac{2}{3}y^{-\frac{1}{3}}\frac{dy}{dx}=0$

Using formula : $\frac{dx^n}{dx}=nx^{n-1}$

$\frac{2}{3}y^{-\frac{1}{3}}\frac{dy}{dx}=-\frac{2}{3}x^{-\frac{1}{3}}$

$\frac{dy}{dx}=\frac{-\frac{2}{3}x^{-\frac{1}{3}}}{\frac{2}{3}y^{-\frac{1}{3}}}$

$\frac{dy}{dx}=-\frac{x^{-\frac{1}{3}}}{y^{-\frac{1}{3}}}$

Substitute the value x= $-3\sqrt3,y=1$

Then, we get

$\frac{dy}{dx}=-\frac{(-3\sqrt3)^{-\frac{1}{3}}}{1}$

$\frac{dy}{dx}=-(-3^{\frac{3}{2}})^{-\frac{1}{3}}=-\frac{1}{-(3)^{\frac{3}{2}\times \frac{1}{3}}}=\frac{1}{\sqrt3}$

Slope of tangent=m= $\frac{1}{\sqrt3}$

Equation of tangent line with slope m and passing through the point $(x_1,y_1)$ is given by

$y-y_1=m(x-x_1)$

Substitute the values then we get

The equation of tangent line is given by

$y-1=\frac{1}{\sqrt3}(x+3\sqrt3)$

$y-1=\frac{x}{\sqrt3}+3$

$y=\frac{x}{\sqrt3}+3+1$

$y=\frac{x}{\sqrt3}+4$

This is required equation of tangent line to the given curve at given point.

8 0

3 years ago