<span>the value of the digit in the tenths place is 5/10 or 0.5
</span>
the value of the digit in the thousandth place
is 5/1000 = 0.005
0.5 = 100 x 0.005
Therefore, the value of the digit in the tenths place is 100 times as much as the value of the digit in the thousandth place
p(x)= x-2
g(x)= 2x^3 + 3x^2 - 11x - 6
first we have to find the zero of the polynomial of x-2
p(x)= x-2 = 0
x=2
therefore,
p(x)= 2x^3 + 3x^2 - 11x - 6
p(2)= 2*2^3 + 3*2^2 - 11*2 - 6
= 2*8 + 3*4 - 11*2 - 6
= 16 + 12 - 22 - 6
= 28-28
= 0
Hope it helped u, ^_^.
Answer:
its look like this
Step-by-step explanation:
It’s d I believe I think I’m not so sure tho I’m pretty sure
