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kifflom [539]
3 years ago
13

How to find a,b and c

Mathematics
1 answer:
alina1380 [7]3 years ago
3 0
33/54 = 44/(a+44)
33(a+44) = 44*54
33a+ 1452 =  2376
33a = 924
    a = 28

c = sqrt (33^2 + 44^2)
c = sqrt(1089 + 1936)
c = sqrt(3025)
c = 55

33/54 = 55/(b+55)
33(b+55) = 55*54
33b+ 1815 =  2970
33b = 1155
    b = 35

answer
a = 28, b = 35, c = 55
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This is important please help
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Answer: C

<u>Step-by-step explanation:</u>

∑ 8(\frac{7}{3})⁽ⁿ⁻¹⁾ from n = 1 to n = 5

n = 1 → 8(\frac{7}{3})⁽¹⁻¹⁾

        = 8                                         = \frac{648}{81}

n = 2 → 8(\frac{7}{3})⁽²⁻¹⁾

         = \frac{56}{3}                                         = \frac{1512}{81}    

n = 3 → 8(\frac{7}{3})⁽³⁻¹⁾

          = \frac{392}{9}                                     = \frac{3528}{81}

n = 4 → 8(\frac{7}{3})⁽⁴⁻¹⁾

          = \frac{2744}{27}                                 = \frac{8232}{81}

n = 5 → 8(\frac{7}{3})⁽⁵⁻¹⁾

          = \frac{19208}{81}                                = \frac{19208}{81}

                                                                            Sum = \frac{33128}{81}

                                                                                    = 408.99

     

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