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Advocard [28]
3 years ago
12

Write down in terms of

Mathematics
1 answer:
Nata [24]3 years ago
5 0

Answer:

-5

Step-by-step explanation:

Here,

t2-t1=20-25=-5

t3-t2=15-20=-5

t4-t3=10-15=-5

t5-t4=5-10=-5

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WILL GIVE 5 STAR IF CORRECT: Chasity purchased a pool for $9,270 using a six-month deferred payment plan with an interest rate o
Verdich [7]

Answer:

$297.41

Step-by-step explanation:

Given that:

Amount = 9270

Derferred period = 6 months = 0.5 yr

Rate = 17.95% = 0.1795

Amount = 9270(1 + 0.1795)^0.5

Amount = 9270(1.1795)^0.5

Amount = 10067.663

PV = 10067.663

Number of months, n = 48

Monthly amount to be paid :

rp = rate per period = 0.1795/12 = 0.0149583

(rp * PV) / 1 - (1 + rp)^-n

(0.0149583 * 10067.663) / 1 - (1 + 0.0149583)^-48

150.5951234529 / 0.5096723

= 295.47441

Closest option is $297.41

6 0
3 years ago
Which expression is a factor of 10 x 2 + 11 x + 3
Eduardwww [97]
Answer: the two factors are (5x + 3) and (2x + 1)

Explanation:

I will find the two factors of 10x² + 11x + 3.

You can use either the quadratic formula of factor.

I will use the quadratic formula:

1)    

x= \frac{b^2 +/- \sqrt{b^2-4ac}  }{2a}

x=  \frac{-11+/- \sqrt{11^2-4(10)(3)} }{(2)(10)}

x = -3/5 and x = -1/2

2) the factors are: x - (-3/5) = 0 and x - (-1/2) = 0

Simplify them.

3) x - (-3/5) = 0

5x + 3 = 0

4) x - (-1/2) = 0

2x + 1 = 0

5) Then the two factors are: (5x + 3) and (2x + 1).

6) verify:

(5x + 3)(2x + 1) = 10x² + 5x + 6x + 3 = 10x² + 11x + 3 which is the original expression.
7 0
3 years ago
Please need help I suck at math ‼️‼️
sdas [7]

Answer:

d

Step-by-step explanation:

6 0
3 years ago
What’s the answer of a multiplying polynomials (3x-1) to the second power and (x+6) to the second power
Vladimir [108]

9x^4+102x^3+253x^2-204x+36 is the result of multiplying (3x-1) to the second power and (x+6) to the second power

<h3><u>Solution:</u></h3>

Given that we have to find the result of multiplying polynomials (3x-1) to the second power and (x+6) to the second power

"Second power" means the term is raised to power of 2

Therefore,

We have to multiply (3x-1)^2 \text{ and }(x+6)^2

\rightarrow (3x-1)^2 \times (x+6)^2

We can use the algebraic identity to expand the above expression

(a+b)^2 = a^2+2ab+b^2\\\\(a-b)^2=a^2-2ab+b^2

Applying these in above expression, we get

\rightarrow ((3x)^2-2(3x)(1)+1^2) \times (x^2+2(x)(6)+6^2)\\\\\rightarrow (9x^2-6x+1) \times (x^2+12x+36)

Multiply each term in first bracket with each term in second bracket

\rightarrow 9x^2(x^2)+(9x^2)(12x)+(9x^2)(36)-6x(x^2)-6x(12x)-6x(36) + x^2+12x+36

Simplify the above expression

\rightarrow 9x^4+108x^3+324x^2-6x^3-72x^2-216x+x^2+12x+36

Combine the like terms

\rightarrow 9x^4+102x^3+253x^2-204x+36

Thus the above expression is the result of multiplying (3x-1) to the second power and (x+6) to the second power

4 0
3 years ago
-3(7+4n)=-8n-29 what is the work and answer
sesenic [268]
Hello there.

<span>-3(7+4n)=-8n-29

First, s</span><span>implify both sides of the equation.
Next, a</span><span>dd 8n to both sides.
After, a</span><span>dd 21 to both sides
Then, d</span><span>ivide both sides by -4
Last, you'll get </span>n=<span>2

Your answer: </span>n=<span>2</span>
4 0
3 years ago
Read 2 more answers
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