Can someone help? I’m almost done with this class.
1 answer:
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Answer: There are 99 three-legged-cows and 28 chickens.
Step-by-step explanation:
Let x be the number of three-legged-cows and y be the number of chickens.
Number of legs in chicken = 2
The according to the question, we have the following equations :-
Multiplying 2 to the equation (1), we get
Now, subtract equation (3) from (2), we get
Put x= 99 in (1), we get
Hence, there are 99 three-legged-cows and 28 chickens.