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AVprozaik [17]
3 years ago
11

If I Kilometer= .6 miles then 25.97 kilometers equals how many miles?

Mathematics
2 answers:
swat323 years ago
5 0

Answer:

155.82 miles

Step-by-step explanation:

You multiply 6 and 25.97 to get your answer.

telo118 [61]3 years ago
4 0

the answer is 155.82 miles

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Whats the solution of 6x+18=12x.
Vadim26 [7]

Answer:

<h2><em><u>x</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>3</u></em></h2>

Step-by-step explanation:

6x + 18 = 12x

=> 18 = 12x - 6x

=> 18 = 6x

=  > x =  \frac{18}{6}

=> <em><u>x</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>3</u></em><em><u> </u></em><em><u>(</u></em><em><u>Ans</u></em><em><u>)</u></em>

6 0
2 years ago
Read 2 more answers
A wildlife preservation group records the number of squirrels in a city park. The first count recorded is 30 squirrels. A second
ipn [44]

Answer:

A F(x)=30x

Step-by-step explanation:

just plug number in to the equations to see which one matches

5 0
3 years ago
Read 2 more answers
I've included two questions. Hopefully you can help me with both. Thanks!
lubasha [3.4K]

Answer:

  1.  value is 0; x-3 is a factor . . . . . . . . . . . . . .third choice

  2.  evaluates at x = -1; remainder is -11 . . . . first choice

Step-by-step explanation:

Dividing f(x) by (x -a) gives ...

  f(x)/(x -a) = g(x) +r/(x -a) . . . . some quotient and a remainder r

If we multiply this expression by (x -a), we see ...

  f(x) = (x -a)g(x) +r

so

  f(a) = (a -a)g(a) +r . . . . . evaluate the above equation at x=a

  f(a) = 0 +r

  f(a) = r . . . . . . . . . a statement of the remainder theorem

If r=0, then x-a is a factor of f(x) = (x-a)g(x).

___

1. We have "a" = 3, and f(3) = 0. Therefore (x-3) is a factor.

__

2. We have "a" = -1, and f(-1) = -11. Therefore the remainder from division by (x+1) is -11.

6 0
3 years ago
Tobeg says the equation 3x + 2y= 270 and y=4/5x + 20 intersect at the point (50,60) is this true how do you know
il63 [147K]

ANSWER

Yes it is very true


<u>EXPLANATION</u>

If the two equations intersect at (50,60) then this point must satisfy the two equations.


3x+2y=270---(1)

We substitute  (50,60)  in to erquation (1)


3(50)+2(60)=270


150+120=270

270=270




y=\frac{4}{5}x+20 ---(2)


We now substitute  (50,60)  in to erquation (2) also


60=\frac{4}{5}(50)+20


60=40+20


60=60


Since the point satisfy all the two equations, it is true that they intersect at (60,50)




3 0
3 years ago
Simplify: j + 5 + 5c
irina [24]
The answer is 5
c
+
j
+
5
5 0
3 years ago
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