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3 years ago

Quadrilateral ABCD is inscribed in this circle.

Mathematics

2 answers:

zheka24 [161]3 years ago

7 0

Rule: Opposite angles of inscribed quadrilaterals are supplementary.
In other words, the opposite angles of inscribed quadrilaterals add to 180 degrees.

A+C = 180
A+74 = 180 ................ plug in the given value for C
A+74-74 = 180-74 .... subtract 74 from both sides
A = 106

Angle A is 106 degrees

Ipatiy [6.2K]3 years ago

5 0

Answer:

Measure of ∠A is 106°

Step-by-step explanation:

We are given that, 'Quadrilateral ABCD is inscribed in the circle'.

So, we get that,

'ABCD is a cyclic quadrilateral' i.e. The sum of the opposite interior angles is 180°.

Thus, we have,

∠A +∠C = 180°

i.e. ∠A + 74° = 180°

i.e. ∠A = 180° - 74°

i.e. ∠A = 106°

Thus, the measure of ∠A is 106°.

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What set of reflections and rotations would carry rectangle ABCD onto itself? Parallelogram formed by ordered pairs A at negativ

pickupchik [31]

Each of the 4 choices has been drawn step by step as follows:

the first transformation is drawn in light grey
the second transformation is drawn in dark grey
the third transformation is described as how it should be.

Choice I, picture I:
Rotate 180°, reflect over the x-axis, reflect over the line y=x

the last transformation should be : reflect with respect to the y-axis

Choice II, picture II:
Reflect over the x-axis, rotate 180°, reflect over the x-axis

the last transformation should be : reflect with respect to the y-axis

Choice III, picture III:
Rotate 180°, reflect over the y-axis, reflect over the line y=x

the last transformation should be : reflect with respect to the x-axis

Choice IV, picture IV:
Reflect over the y-axis, reflect over the x-axis, rotate 180°

the last transformation should be : rotate 180° CORRECT!

Answer: Reflect over the y-axis, reflect over the x-axis, rotate 180°

6 0

3 years ago

Read 2 more answers

HELPP!!!!!!!!!!!!!!!!

Anvisha [2.4K]

Answer:

Step-by-step explanation:

We'll take this step by step. The equation is

$8-3\sqrt[5]{x^3}=-7$

Looks like a hard mess to solve but it's actually quite simple, just do one thing at a time. First thing is to subtract 8 from both sides:

$-3\sqrt[5]{x^3}=-15$

The goal is to isolate the term with the x in it, so that means that the -3 has to go. Divide it away on both sides:

$\sqrt[5]{x^3}=5$

Let's rewrite that radical into exponential form:

$x^{\frac{3}{5}}=5$

If we are going to solve for x, we need to multiply both sides by the reciprocal of the power:

$(x^{\frac{3}{5}})^{\frac{5}{3}}=5^{\frac{5}{3}}$

On the left, multiplying the rational exponent by its reciprocal gets rid of the power completely. On the right, let's rewrite that back in radical form to solve it easier:

$x=\sqrt[3]{5^5}$

Let's group that radicad into groups of 3's now to make the simplifying easier:

$x=\sqrt[3]{5^3*5^2}$ because the cubed root of 5 cubed is just 5, so we can pull it out, leaving us with:

$x=5\sqrt[3]{5^2}$ which is the same as:

$x=5\sqrt[3]{25}$

8 0

3 years ago

What is the product of 6+5i and 4+7i?

Vilka [71]

(6 + 5i)(4 + 7i) = 24 + 42i + 20i + 35i²
= 35i² + 62i + 24

The product of 6+5i and 4+7i is 35i² + 62i + 24.

8 0

4 years ago

Which represents the value of point d on the number line

CaHeK987 [17]

Answer:

Step-by-step explanation:

5 0

3 years ago

2. What step did Mikayla do wrong when she solved this

Lunna [17]

Mikayla subtracted 4 from both sides in the beginning when she should've added it to both sides to cancel it out on the right. the correct answer should actually be x=1

5 0

3 years ago

Read 2 more answers

Quadrilateral ABCD ​ is inscribed in this circle.

Quadrilateral ABCD is inscribed in this circle.