I don’t understand this question
Answer:
you mind if i take these points?
Explanation:
Answer:
The correct answer to the following question will be "Θ(n2)
". The further explanation is given below.
Explanation:
If we're to show all the objects that exist from either the first as well as the second vector, though not all of them, so we'll have to cycle around the first vector, so we'll have to match all the objects with the second one.
So,
This one takes:
= 
And then the same manner compared again first with the second one, this takes.
=
Therefore the total complexity,
= Θ(n2)
Answer:
Information security policy are used for the prevention of intruders hacking a network when an organization start getting IT related attacks.
Explanation:
Information security policy are used for the prevention of intruders hacking a network when an organization start getting IT related attacks.
An information security policy are set of rules/policies designed to guide employees for the protection of the security of company information and IT systems. The reasons for these policies are:
- It defines what is required from organization’s employees for the security of the IT systems
- Information security policies provide a means to secure the organization against external and internal threats
- Information security policies are a mechanism to for ensuring an organization’s legal and ethical responsibilities
- Information security policies are created to hold each employee responsible with regard to information security
Answer:
The receiver will not detect the error.
Explanation:
The byte sent by transmitter: 10101010
The byte received by receiver due to channel noise: 10011010
If you see the bold part of the both sent and received bytes you can see that the number of bits changed is 2.
The two communicating devices are using a single-bit even parity check. Here there are two changed bits so this error will not be detected as this single bit even parity check scheme has a limit and it detects the error when the value of changed bit is odd but here it is even.
This parity scheme basically works well with the odd number of bit errors.
