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3 years ago

A+b+c=75 find out a,b and c

Mathematics

1 answer:

igor_vitrenko [27]3 years ago

3 0

A+B+C= 25+25+25=75 so 25 could be your answer

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3. Con la finalidad de contar con un alimento para animales con un valor nutritivo

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3 years ago

The cost of 4 pounds of bananas is $1.88. What is the constant of proportionality that relates the cost in dollars, y, to the nu

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5 0

3 years ago

Read 2 more answers

Write an algebraic expression for the word phrase. five fewer than d days d – 5 5 + d 5 – d d + 5

Troyanec [42]

Answer:

(d-5)

Step-by-step explanation:

we know that

The phrase"five fewer than d days" is equal to subtract 5 from the number d

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7 0

2 years ago

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Solve and show your work please!x+7=2(3x-4)

Brrunno [24]

x + 7 = 2(3x - 4) Remove the brackets

x + 7 = 2*3x - 4*2

x + 7 = 6x - 8 Subtract 7 from both sides.

x + 7 - 7 = 6x - 8 - 7

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x - 6x = - 15

-5x = - 15 Divide by -5

-5x/-5 = -15/-5

x = 3

6 0

3 years ago

A car valued at £18000 at the start of 2017, depreciated in value by 5% each year for 3 years. How much did it lose in value ove

Anna11 [10]

<u>Answer:</u>

The amount lost over the 3 years s 2567.25£

<u>Explanation:</u>

$\mathrm{F}=\mathrm{I} \times\left(1-\left(\frac{r}{100}\right)\right)^{\mathrm{n}}$

where F = final value after n years

I = initial value of the car in 2017 = £18000 (given)

Since the value is depreciated 5% every year for 3 years,

r = percentage rate of depreciation = 5% (given)

n = 3 years

Substituting these values in formula, we get

$\mathrm{F}=18000 \times\left(1-\frac{5}{100}\right)^{3}$

= $18000 \times\left(\frac{95}{100}\right)^{3}$

= 15432.75£ which is the value of the car after 3 years

Finally 18000-15432.75 = 2567.25£ is the amount lost over this period.

6 0

3 years ago