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adelina 88 [10]
3 years ago
11

Which are polynomials

Mathematics
1 answer:
Minchanka [31]3 years ago
4 0

<u>Given</u>:

Given that there are 4 expressions.

We need to determine the expressions that are polynomials.

<u>Option a:</u> -7x^2+\frac{5}{3x}

In the second term of the expression, the constant is divided by a variable.

For an expression to be a polynomial, it should not divided by a variable.

Hence, the expression -7x^2+\frac{5}{3x} is not a polynomial.

Thus, Option a is not the correct answer.

<u>Option b</u>: -x^{2}+5 x

The given expression satisfies the conditions of the polynomial.

Hence, the expression -x^{2}+5 x is a polynomial.

Thus, Option b is the correct answer.

<u>Option c</u>: 6 x^{2}+5 x

The given expression satisfies the conditions of the polynomial.

Hence, the expression 6 x^{2}+5 x is a polynomial.

Thus, Option c is the correct answer.

<u>Option d</u>: x^{2}+5 x^{\frac{1}{5}}

The second term of the expression contains the exponent \frac{1}{5}

For an expression to be a polynomial, the fractional exponent is not allowed.

Hence, the given expression x^{2}+5 x^{\frac{1}{5}} is not a polynomial.

Thus, Option d is not the correct answer.

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What is the fully simplified answer to sqrt(7/18) + sqrt(5/8) - sqrt(7/2)
NeX [460]

Answer:

=\frac{-4\sqrt{7}+3\sqrt{5}}{6\sqrt{2}}

Step-by-step explanation:

Given expression as:

=\sqrt{\frac{7}{18}}+\sqrt{\frac{5}{8}}-\sqrt{\frac{7}{2} }

We need to simplify the given expression.

Solution:

We have:

=\sqrt{\frac{7}{18}}+\sqrt{\frac{5}{8}}-\sqrt{\frac{7}{2} }

Rewrite the expression as:

=\frac{\sqrt{7}}{3\sqrt{2}} - \frac{\sqrt{7}}{\sqrt{2}} +\frac{\sqrt{5}}{2\sqrt{2}}

\frac{\sqrt{7}}{\sqrt{2} } is a common factor to the first two terms.

Using distributive property we can factor out \frac{\sqrt{7}}{\sqrt{2} } from the first two terms.

=\frac{\sqrt{7}}{\sqrt{2}}(\frac{1}{3} -1)  +\frac{\sqrt{5}}{2\sqrt{2}}

=\frac{\sqrt{7}}{\sqrt{2}}(\frac{1-3}{3})  +\frac{\sqrt{5}}{2\sqrt{2}}

=\frac{\sqrt{7}}{\sqrt{2}}(\frac{-2}{3})  +\frac{\sqrt{5}}{2\sqrt{2}}

=-\frac{2\sqrt{7}}{3\sqrt{2}} +\frac{\sqrt{5}}{2\sqrt{2}}

\sqrt{2} is common factor, so we can factor \sqrt{2} from the above expression.

=\frac{1}{\sqrt{2} }( -\frac{2\sqrt{7}}{3} +\frac{\sqrt{5}}{2})

=\frac{1}{\sqrt{2} }( \frac{-2\times 2\sqrt{7}+3\times \sqrt{5}}{6})

=\frac{1}{\sqrt{2} }( \frac{-4\sqrt{7}+3\sqrt{5}}{6})

=\frac{-4\sqrt{7}+3\sqrt{5}}{6\sqrt{2}}

Therefore, we get simplified answer as.

=\frac{-4\sqrt{7}+3\sqrt{5}}{6\sqrt{2}}

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