PEMDAS!
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SA = s2<span> + 2 × s × </span>l<span> Is the formula for the surface area of a square pyramid</span>
DT/dt=k(T-38)
ln(T-38) = kt+C
T=38 + Ce^(-kt)
Since T(0)=75, 75 = 38+C, so C=37
Since T(30)=60, 60 = 38+37e^(-30k), so k = -ln(22/37)/30 ~= -0.017329
T(60) = 38+37e^(-0.017329*60) = 51.1°F
Answer:
(x+)^3
Step-by-step explanation:
Answer:
27 ft
the maximum height of the arrow is 27 ft
Step-by-step explanation:
Given;
The height of the arrow is given by the function;
h(t) = -16t^2 + 32t + 11
Maximum height is at point when dh(t)/dt = 0.
Differentiating h(t), we have;
dh/dt = -32t + 32 = 0
Solving for t;
-32t = -32
t = -32/-32 = 1
t = 1 (time at maximum height is t = 1)
Substituting t=1 into h(t), to determine the value of maximum height;
h(max)= -16(1^2) + 32(1) + 11
h(max) = 27 ft
the maximum height of the arrow is 27 ft.
