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miv72 [106K]
3 years ago
13

​Tara, a​ pharmacist, is planning on opening her own pharmacy. Tara currently earns​ $50,000 a year at her job. She has calculat

ed that it will cost her​ $6,000 in rent and utilities and​ $25,000 for an assistant per year to run her pharmacy. What is the amount of opportunity cost that Tara incurs in running her own​ pharmacy?
Business
1 answer:
kolbaska11 [484]3 years ago
6 0

Answer:

$81,000

Explanation:

The computation of the amount of opportunity cost for running her own​ pharmacy is shown below:

= Earning as a job + rent expenses + utilities expenses

= $50,000 + $6,000 + $25,000

= $81,000

By adding the earnings, rent expenses, and the utility expenses we can get the opportunity cost for running her own​ pharmacy

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c. 03

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B-section 404

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Anderson Manufacturing​ Co., a small fabricator of​ plastics, needs to purchase an extrusion molding machine for ​$180 comma 000
vlabodo [156]

Answer:

1st     46,398.83

2nd    49,646.74

3rd      53,122.02

4th      56,840.56

5th       60,819.40

Explanation:

given a growing annuity we have to solve for the installement

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FV = PV (1+r)^5 = 180,000 x 1.14^5 =  346,574.62  

grow rate 0.07

interest rate 0.14

n = time     5

346,574.62 = C  \times \frac{1-(1+0.07)^{5}\times (1+0.14)^{-5} }{0.14 - 0.07}

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Now, to determiante the subsequent payment we multiply by the grow rate of 1.07

6 0
3 years ago
This morning, you purchased a stock that will pay an annual dividend of $1.90 per share next year. You require a 12 percent rate
Luba_88 [7]

Answer:

The correct answer is $2.43.

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=\frac{1.90}{12-3.5}

=\frac{1.90}{0.085}

=$22.35

The stock price at year 3 will be

=\frac{dividend*(1-growth rate)^3}{required rate of return-growth rate}

=\frac{1.90*(1+0.035)^3}{12-3.5}

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=$24.78

The capital gain will be

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=$2.43

8 0
3 years ago
Assume that the hourly cost to operate a commercial airplane follows the normal distribution with a mean of $5,793 per hour and
AfilCa [17]

Answer:

x1 = 4891.294

Explanation:

given data

mean μ =  $5,793

standard deviation  σ =  $439

solution

we know here that

P(x < x1 ) = 0.02     .................1

so

P(\frac{x-\mu }{\sigma } < \frac{x1-\mu }{\sigma }) = 0.02

so

P(z < \frac{x1-\mu }{\sigma }) = 0.02

\frac{x1-\mu }{\sigma }  = invNorm(0.02)

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we use here table for invNorm(0.02) and put value in eq 2

x1 = 5793 + 439 × (-2.054 )

x1 = 4891.294

8 0
3 years ago
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