Question

A football team was training for four hours during the first hour they practice for five eights open hour during the second hour they practiced for 2/3 of an hour join the last two hours the first practice for 3/5 of an hour took a 1/2 hour break and then practice the rest of the time how much time did they spent practicing in total?

Answer 1

Answer:

$2\frac{19}{24}$ hours

Step-by-step explanation:

Given,

The total numbers of hours allotted = 4,

In first 2 hours,

Practice in first hour = $\frac{5}{8}$ hour,

In second hour = $\frac{2}{3}$ hour,

Remaining hours = 4 - 2 = 2 hours,

In remaining 2 hours,

Practice in first hour = $\frac{3}{5}$ hour

Rest time = $\frac{1}{2}$ hour

Remaining time or practice in second hour = $2-\frac{1}{2}-\frac{3}{5}=\frac{20-5-6}{10}=\frac{9}{10}$

Total time of practicing = $\frac{5}{8}+\frac{2}{3}+\frac{3}{5}+\frac{9}{10}$

$=\frac{75+80+72+108}{120}$

$=\frac{335}{120}$

$=2\frac{19}{24}$ hours