Answer:
2.37 x 10 ^ -5
Step-by-step explanation:
Hello :
the area of a circle is : A= πr²..........r : <span>radius
in this exercice : r =1 A = </span>π(1)² =π m²
Answer: No, it is not possible
A triangle can only have 1 obtuse interior angle, leaving the exterior angle next to it to be acute. For example, if you have an interior angle of 120 (obtuse) then the adjacent exterior angle is 60 (acute)
The other two interior angles must be acute if you go with 1 obtuse angle, which leaves the corresponding exterior angles to be obtuse. If you wanted the exterior angles to be all acute, then you would need 3 obtuse interior angles, but that is not possible.
Why isn't it possible to have 3 obtuse angles? Consider a triangle with interior angles A, B, C. The three angles must add to 180
A+B+C = 180
If A,B,C were all larger than 90, then
A > 90
B > 90
C > 90
A+B+C > 90+90+90
A+B+C > 270
but that contradicts A+B+C being equal to 180
ANSWER:
A diagonal fold which runs from the bottom-left corner to the top-right corner.
This would be the angle bisector of XAB as it would run directly through the centre of the angle, thus bisecting it.
I have attached an image which visually represents this. The blue lines are meant to be the angle XAB while the red line is the diagonal fold / angle bisector.
Hope this helps! <3
<span>The elimination method for solving systems of linear equations uses the addition property of equality. You can add the same value to each side of an equation.</span>
<span>So if you have a system: x – 6 = −6 and x + y = 8, you can add x + y to the left side of the first equation and add 8 to the right side of the equation. And since x + y = 8, you are adding the same value to each side of the first equation.</span>
