The second side of a triangular deck is 4 feet longer than the shortest side
(s+4) = the 2nd side
and a third side that is 4 feet shorter than twice the length of the shortest side.
(2s-4) = the 3rd side
If the perimeter of the deck is 48 feet, what are the lengths of the three sides?
s + (s+4) + (2s-4) = 48
Combine like terms
s + s + 2s + 4 - 4 = 48
4s = 48
s = 48/4
s = 12 ft is the shortest side
I'll let you find the 2nd and 3rd sides, ensure they add up to 48
Hope this helps!
Answer:
y = ⅔x - 5
Step-by-step explanation:
To write the equation, find the slope (m), to enable you write the equation of the line in point-slope form given a point, (-3, -7) that the line passes through.
Since the line is parallel to 2x - 3y = 24,, it would have the same slope (m) value.
Rewrite 2x - 3y = 24 in slope-intercept form.
Thus:
2x - 3y = 24
-3y = -2x + 24
y = ⅔x - 12
The slope of 2x - 3y = 24 is ⅔. Therefore, the line that is parallel to 2x - 3y = 24 is also ⅔.
To write the equation of the line, substitute (a, b) = (-3, -7) and m = ⅔ into y - b = m(x - a)
Thus:
y - (-7) = ⅔(x - (-3))
y + 7 = ⅔(x + 3)
y + 7 = ⅔x + 2
y = ⅔x + 2 - 7
y = ⅔x - 5
Answer:
Step-by-step explanation:
Answer:
(no solutions exist)
Step-by-step explanation: