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Anit [1.1K]
3 years ago
14

When working with a large worksheet, you can split the window into ____ panes.?

Computers and Technology
1 answer:
krek1111 [17]3 years ago
5 0
When working with a large worksheet, you can split the window into two or four panes.
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A ________ algorithm is a method of locating a specific item of information in a larger collection of data.
pav-90 [236]
A .) Sort

more ... To arrange or group in a special way (such as by size, type or alphabetically).
6 0
3 years ago
Question 1. (50 points) 1.Write a program that computes information related to a sequence of entries regarding age of customers.
schepotkina [342]

Answer:

The solution code is written in Python 3:

  1. count = 0
  2. totalAge = 0
  3. group1_count = 0    #age < 10
  4. group2_count = 0    #age 10 - 20
  5. group3_count = 0    #age 20 - 40
  6. group4_count = 0    #age > 40
  7. group1_total = 0    #subtotal age <= 10
  8. group2_total = 0    #subtotal age 11 - 20  
  9. group3_total = 0    #subtotal age 21 - 40  
  10. group4_total = 0    #subtotal age > 40
  11. age = int(input("Input an age: "))
  12. youngest = age
  13. oldest = age
  14. while(age != -1):
  15.    count += 1
  16.    totalAge += age
  17.    
  18.    if(age <= 10):
  19.        group1_count += 1
  20.        group1_total += age
  21.    elif(age <= 20):
  22.        group2_count += 1
  23.        group2_total += age
  24.    elif(age <= 40):
  25.        group3_count += 1
  26.        group3_total += age
  27.    else:
  28.        group4_count += 1
  29.        group4_total += age
  30.    if(youngest > age):
  31.        youngest = age  
  32.    
  33.    if(oldest < age):
  34.        oldest = age  
  35.    age = int(input("Input an age: "))
  36.    
  37. totalCustomer = count  
  38. avgAge = totalAge / count  
  39. rangeAge = oldest - youngest  
  40. avgAgeGroup1 = group1_total / group1_count  
  41. avgAgeGroup2 = group2_total / group2_count  
  42. avgAgeGroup3 = group3_total / group3_count  
  43. avgAgeGroup4 = group4_total / group4_count  
  44. print("The total number of customers: " + str(totalCustomer))
  45. print("Total number of customer in Group 1 (<=10): " + str(group1_count))
  46. print("Total number of customer in Group 2 (11 - 20): " + str(group2_count))
  47. print("Total number of customer in Group 3 (21 - 40): " + str(group3_count))
  48. print("Total number of customer in Group 4 (> 40): " + str(group4_count))
  49. print("Average age for all customer: " + str(avgAge))
  50. print("Youngest age: " + str(youngest))
  51. print("Oldest age: " + str(oldest))
  52. print("The range of age: " + str(rangeAge))
  53. print("Average age for group 1 (<=10): " + str(avgAgeGroup1))
  54. print("Average age for group 2 (11 - 20): " + str(avgAgeGroup2))
  55. print("Average age for group 3 (21 - 40): " + str(avgAgeGroup3))
  56. print("Average age for group 4 (> 40): " + str(avgAgeGroup4))

Explanation:

Firstly, create the counter variables (e.g. count, group1_count, group2_count etc ) to track the total number of customer and number in each age group. Besides, create variables to hold the value of total of age and sub-total of each age group (Line 1 - 10). We presume there are only four age groups.

Next, prompt user to input the first age (Line 12)

Create variable youngest and oldest to track the lowest and highest age (Line 13 -14). At the moment, set the first input age as value of youngest and oldest.

Create a while loop with sentinel value  -1 (Line 16). Within the loop, track the customer occurrence by incrementing counter variables by one (Line 17, 21, 24, 27 & 30). At the same time, add the current input age to totalAge and to group total (Line 18, 22, 25, 28, & 31).

If the current youngest value is bigger than the current input age, we set the current age to youngest (Line 33- 34).

If the current oldest value is smaller than the current input age, we set the current age to oldest (Line 36- 37).

After terminating the loop with -1, calculate the average age for all customers and for each age group and the range of age (Line 42- 48)  

At last, display all the required calculation results using print function (50 - 62)

7 0
3 years ago
What is the least number of bits you would need to borrow from the network portion of a Class B subnet mask to get at least 130
Tatiana [17]

Answer: Eight

Explanation:

A class B address is 255.255.0.0. We need to borrow 8 bits from the network portion to have atleast 130 host per subnet.

11111111.00000000.00000000.00000000

8 0
3 years ago
. In testing, what is the role of an oracle?
ikadub [295]

Answer:

The role of test oracle is to determine if a test has passed or failed. Oracle compares the outputs of the system under a  test, for a given test-case input, and the output(s) that should have. A test oracle works on specifying constraints on the output(s) for a set of inputs. An oracle could be:

  • a program which tells if the output is correct.
  • documentation that specifies the correct output for inputs.
  • a human that can tell whether it is correct an output.

5 0
3 years ago
For two integers m and n, their GCD(Greatest Common Divisor) can be computed by a recursive function. Write a recursive method g
konstantin123 [22]

Answer:

In Python:

def gcd(m,n):

if n == 0:

 return m

elif m == 0:

    return n

else:

 return gcd(n,m%n)

Explanation:

This defines the function

def gcd(m,n):

If n is 0, return m

<em> if n == 0: </em>

<em>  return m </em>

If m is 0, return n

<em> elif m == 0: </em>

<em>     return n </em>

If otherwise, calculate the gcd recursively

<em> else: </em>

<em>  return gcd(n,m%n)</em>

<em />

<em>To call the function to calculate the gcd of say 15 and 5 from main, use:</em>

<em>gcd(15,5)</em>

6 0
3 years ago
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