Answer:
B. deep organizational structure
Explanation:
A website with a deep organizational structure is a positive attribute that improves site performance.
"The increased availability of mobile digital devices has had a positive impact on how young people use their free time."
There are many different views that you could take upon this subject.
1) You could say that the increased availability of mobile digital devices has allowed children to increase their academic success, by being able to search for and complete assignments using these devices.
2) You could say that the increased availability of mobile digital devices allows for children to occupy themselves by providing games, videos, books, and other things to provide them with entertainment, a learning experience, and more.
Hope this helps!
Answer:
0.01 second ; 0.008 seconds; 800 seconds
Explanation:
Given that:
Sending rate = 1000 bps
Rate of 1000 bps means that data is sent at a rate of 1000 bits per second
Hence, to send out 10 bits
1000 bits = 1 second
10 bits = x
1000x = 10
x = 10 / 1000
x = 0.01 second
2.)
A single character 8 - bits
1000 bits = 1 second
8 bits = (8 / 1000) seconds
= 0.008 seconds
3.)
100,000 characters = (8 * 100,000) = 800,000
1000 bits = 1 second
800,000 bits = (800,000 / 1000)
= 800 seconds
Answer:
Answered below
Explanation:
//Program is written in Java programming language
Class RegularPolygon{
int sides = 0;
int length = 0;
}
public void randomize(RegularPolygon polygon){
int randomSides = (int) 10 + (Math.random() * 20);
double randomLength = 5 + (Math.random() * 11);
polygon.sides = randomSides;
polygon.length = randomLength;
}
Answer:
(a) someFunc(3) will be called 4 times.
(b) For non negative number n someFunc method calculates 2^2^n.
Explanation:
When you call someFunc(5) it will call someFunc(4) two time.
So now we have two someFunc(4) now each someFunc(4) will call someFunc(3) two times.Hence the call to someFun(3) is 4 times.
someFunc(n) calculates someFunc(n-1) two times and calculates it's product.
someFunc(n) = someFunc(n-1)^2..........(1)
someFunc(n-1)=someFunc(n-2)^2..........(2)
substituting the value form eq2 to eq 1.
someFunc(n)=someFunc(n-2)^2^2
.
.
.
.
= someFunc(n-n)^2^n.
=2^2^n
2 raised to the power 2 raised to the power n.
