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tiny-mole [99]
4 years ago
14

Multiply the complex numbers. (5+1i)(-3+2i)

Mathematics
1 answer:
Mumz [18]4 years ago
5 0

Answer:

-17+7i

Step-by-step explanation:

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A toy car costing $50 is reduced by 10% in the sale. How much does it cost now
nekit [7.7K]

Answer:

5

Step-by-step explanation:

you do 50 divided by 10 wich equals 5

7 0
4 years ago
Paula bought a jacket on sale for 6 less that half it’s original price.She paid 36 for the jacket.What was the original price?
grigory [225]

Answer:

$84

Step-by-step explanation:

Add 6 to 36, then multiply by 2

4 0
3 years ago
Read 2 more answers
What number set does 0 belong to
GuDViN [60]

Whole, integer, and rational

3 0
3 years ago
How do you do these problems?
Angelina_Jolie [31]

Answer:

18e⁶

⁵/₁₂₈

Step-by-step explanation:

Rₙ(x) = f⁽ⁿ⁺¹⁾(c) / (n+1)! (x − a)ⁿ⁺¹, and a < c < x.

f(x) = eˣ, a = 0, and n = 1.  Thus R₁ is:

R₁(x) = f"(z)/2! x²

R₁(x) = eᶻ/2 x²

|R₁| is a maximum when |f"(z)| is a maximum.  On the domain 0 < z < 6, that maximum is e⁶.  At x = 6, the upper bound of |R₁| is:

|R₁| = 18e⁶

This time, f(x) = 1 / √(1 + x) = (1 + x)^-½.  a = 0, and n = 2.

R₂(x) = f⁽³⁾(z)/3! x³

Find f⁽³⁾(x):

f'(x) = -½ (1 + x)^-³/₂

f"(x) = ¾ (1 + x)^-⁵/₂

f⁽³⁾(x) = -¹⁵/₈ (1 + x)^-⁷/₂

On the domain -½ < z < 0, |f⁽³⁾(z)| is a maximum at z = 0.

|f⁽³⁾(z)| = ¹⁵/₈

Therefore, at x = -½, the upper bound of R₂ is:

|R₂| = (¹⁵/₈)/6 |(-½)³|

|R₂| = ⁵/₁₂₈

8 0
3 years ago
What is nearest whole number to 63.62
kvv77 [185]

Answer:

64

Step-by-step explanation:

Looking at the number 63.62, you see that 6 comes immediately after the decimal point.

Now if the number after the decimal point is more than 5 we round up by adding one to the number just before the decimal point which is 3 in this case.

Assuming the number after the decimal point was less than 5 we would round down adding nothing to the number just before the decimal point.

8 0
4 years ago
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