Think: You're treating the numerator and the denom. in precisely the same way. In doing so you are NOT changing the value of the fraction, only the appearance.
Example: start with 2/3. Mult num. and den. both by 7: 14/21.
2/3 and 14/21 result in precisely the same decimal fraction, showing that the latter set of fractions is equivalent to the former set.
Answer:
40
Step-by-step explanation:
why? because 40x40=1600
Answer:
g(1) = 0
There is a remainder of 10 so you can automatically cross out 3 and 4.
That’s too much Pie and it’s waste a lot of money yooo and why would he do that dang wow :(
Answer:
Lol I'll help you. So for the 1st problem, you need to subtract 7x from 4x but if your looking for and answer then x=2. For the 2nd problem subtract 3x-5x and 7 + 9 which brings you to -2x - 16 which means you would have to find x in this problem which means x has to be a negative. The negative answer is x= -32 since a negative x a negative is a positive. Which brings you to 16-16 and then 0. For the third one, you need to change the problem. Turn it into 5x - x = 4 + 8 which brings you to 4x = 12 making x =3. and for number 4 you need do the same as we just did and do 11x - 6x - 3x and then do 20 - 6 which brings you to 2x = 14 which makes x=7.
Step-by-step explanation: