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Dmitry [639]
3 years ago
10

Two similar polygons have areas of 4 square inches and 64 square inches. The ratio of a pair of corresponding sides is 1/4. True

False
Mathematics
2 answers:
Zanzabum3 years ago
8 0

Answer:

<u><em>True</em></u>

step-by-step explanation:

Just in case you needed a second opinion.

konstantin123 [22]3 years ago
3 0

Answer:

That is true

Step-by-step explanation:

The ratio is a one-to-one measure, literally a ratio of the sides in reduced form.  The area is that one-to-one ratio squared.

Our numbers are already squared, so in order to find the one-to-one we have to take the square roots of both of them.  

\frac{\sqrt{4} }{\sqrt{64} } =\frac{2}{8} =\frac{1}{4}.

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Choose the inequality that represents the following graph.
inysia [295]

Answer:

C

Step-by-step explanation:

3 0
2 years ago
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In the figure above, the measure of &lt;BDE is 20 and CD is perpendicular to DE. What is the measure of &lt;ADC ?​
notsponge [240]

Answer:

∠ ADC = 110°

Step-by-step explanation:

∠ CDE = 90° ( angle between perpendicular lines ) , then

∠ CDB + ∠ BDE = 90°

∠ CDB + 20° = 90° ( subtract 20° from both sides )

∠ CDB = 70°

∠ ADC and ∠ CDB are adjacent angles on a straight line and sum to 180° , so

∠ ADC + ∠ CDB = 180° , that is

∠ ADC + 70° = 180° ( subtract 70° from both sides )

∠ ADC = 110°

6 0
2 years ago
Area of the following kite?
MakcuM [25]

Answer:

i think A=20

A=pq/2 =4·10/2 =20

Hope i helped

-lvr

6 0
3 years ago
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Yan is climbing down a ladder. Each time he descends four rungs on the ladder, he stops to see how much farther he has to go
anastassius [24]

Question:

Yan is climbing down a ladder. Each time he descends 4 rungs on the ladder, he stopped to see how much farther he has to go. If Yan made eight stops with no extra steps, which expression best shows another way to write the product of the number of ladder rungs that Yan and climbed?

4+4+4+4

8+8+8+8

(-1)(4+4+4+4)

(-8) + (-8) + (-8) + (-8)

Answer:

Total = (-8) +(-8) +(-8) +(-8)

Step-by-step explanation:

Given

<em></em>Rungs = -4<em> --- It is negative because he is climbing down</em>

Steps = 8

Required

An expression for the number of rungs climbed

To do this, we simply multiply the number of rungs by the steps taken.

Total = Rungs * Steps

Total = -4 * 8

This can be rewritten as:

Total = -8 * 4

The product, when written as sum is:

Total = (-8) +(-8) +(-8) +(-8)

8 0
3 years ago
The line tangent to the graph of g(x) = x^{3}-4x+1 at the point (2, 1) is given by the formula
Usimov [2.4K]

well, about A and D, I just plugged the values on the slope formula of

\bf \begin{array}{llll} g(x)=x^3-4x+1\\ L(x) = 8(x-2)+1 \end{array} \qquad \begin{cases} x_1=1.9\\ x_2=2.1 \end{cases}\implies \cfrac{f(b)-f(a)}{b-a}

for A the values are 8.01 and 8.0, so indeed those "slopes" are close. \textit{\huge \checkmark}

for D the values are -2.25 and 8.0, so no dice on that one.

for B, let's check the y-intercept for g(x), by setting x = 0, we end up g(0) = 0³-4(0)+1, which gives us g(0) = 1.

checking L(x) y-intercept, well, L(x) is in slope-intercept form, thus the +1 sticking out on the far right is the y-intercept, so, dice. \textit{\huge \checkmark}

for C, well, the slope if L(x) is 8, since it's in slope-intercept form, the derivative of g(x) is g'(x) = 3x² - 4, and thus g'(0) = -4, so no dice.

for E, do they intercept at (2,1)?  well, come on now, L(x) is a tangent line to g(x), so that's a must for a tangent. \textit{\huge \checkmark}

for F, we know the slope of the line L(x) is 8, is g'(2) = 8?  let's check

recall that g'(x) = 3x² - 4, so g'(2) = 3(2)² - 4, meaning g'(2) = 8, so, dice. \textit{\huge \checkmark}

6 0
3 years ago
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