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2 years ago

If 18 , x , y , -3 are in A.P then find x + y.

Mathematics

1 answer:

AleksandrR [38]2 years ago

6 0

Answer:

Step-by-step explanation:

If this is an arithmetic progression, then there is a common difference.

-3-18 = -21

-21/3 = -7

18 - 7 = x

x = 11

11 - 7 = y

y = 4

4 - 7 = -3

x + y

11 + 4 = 15

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Evaluate a + 6 for a = 10?<br><br>6<br>16<br>60

zzz [600]

The answer would be 16
Because 10+6=16

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3 years ago

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Write a paragraph (4-5 sentences) explaining how we can help or change racism to black people

Nuetrik [128]

Answer

A few ways we could stop racism against black people in this country is to stop the perpepuation of black stereotypes in media. Such as the loud, aggressive black man, or the rude, catty black woman. It causes a harmful view on black people and can result in racial profiling. Another way to combat this racism is to fight off systemic racism. Black people who have unique names, usually African names, are more likely to get turned down for a job when they turn in their resume to an establishment. This is because they automatically assume that they'll be trouble, and won't be a good worker.

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2 years ago

Which rules of exponents will be used to evaluate the expression. Check all that apply

julia-pushkina [17]

Hello!

The answer are:

- Product of powers.

- Power of a power.

- Negative exponents.

Let's solve it!

It's a math rule that we must solve first what's into a brake or parenthesis, so,

First: Product of powers $[(7)^{5}*(7)^{3}]$

According to the exponent's law, we have a product of powers case, so, we need to sum the exponents and keep the base

Exponents: 5 and 3

Base: 7

Applying it we have:

$(7)^{5+3}$

$(7)^{8}$

Then,

We have a power of a power case, which involves multiplying the exponents:

$[(7)^{5}*(7)^{3}]^{-4}$

Exponents: 3 and -4

Then,

$(7)^{8*-4}$

Finally, we can apply the negative exponents, the negative exponent's rules state that negative exponents are the reciprocal of the positive exponents,

So, we will have that:

$(7)^{-32}=\frac{1}{7^{32} }$