If you are doing a literal equation all you have to do is isolate the h.
First get rid of the fraction by multiplying both sides by 2.
2a=bh
Then divide both sides by b.
2a/b=h
Hope this helps!
Answer:
The radius of circle B is 6 times greater than the radius of circle A
The area of circle B is 36 times greater than the area of circle A
Step-by-step explanation:
we have
<em>Circle A</em>

The radius of circle A is
-----> the radius is half the diameter
<em>Circle B</em>

Compare the radius of both circles


The radius of circle B is six times greater than the radius of circle A
Remember that , if two figures are similar, then the ratio of its areas is equal to the scale factor squared
All circles are similar
In this problem the scale factor is 6
so

therefore
The area of circle B is 36 times greater than the area of circle A
Hello,
As h(x) is a bijection,
range(h(x))=dom(h^(-1)(x))={0,1,2,3}
Answer C
Answer:
6 m
Step-by-step explanation:
The volume of a cone is found by
, so we can plug the values in to get 6pi * r^2 / 3 = 72pi, or 6pi * r^2 = 216 pi, so r^2 = 36 and the radius is 6 m.
Answer:
Step-by-step explanation:
- <em>Regular hexagons have a property that cutting off the triangles obtained by joining the midpoints of consecutive sides leaves a hexagon of 3/4 of the area.</em>
This means the area of each hexagon inside out starting from the one with unit area is 4/3 of the previous one.
- 99 ⇒ 1
- 98 ⇒ 1*4/3
- 97 ⇒ 1*(4/3)²
- ...
- 1 ⇒ (4/3)⁹⁹⁻¹
<u>The original hexagon has the area of:</u>