We are given the area of the region under the curve of the function f(x) = 5x + 7 with an interval [1, b] which is 88 square units where b > 1
We need to find the integral of the function f(x) = 5x + 7 with the limits 1 and b
5/2 x^2 + 7x (limits: 1, b)
substitute the limits:
5/2 (1^2) + 7 (1) - 5/2 b^2 + 7b = 0
solve for b
Then after solving for b, this would be your interval input with 1: [1, b].<span />
Answer:
Step-by-step explanation:
Graph the parent function y = |x|. This graph has a v shape with vertex at (0, 0) and opens up.
Now translate the entire graph 6 units to the right. The vertex will now be at (6, 0).
Finally, translate this most recent graph 4 units down. The vertex will now be at (6, -4).
Idk but ima try to figure it out ok
A = x > -3 and x < 4
B = x >withlineunder -3 and x <withlineunder 4
C = X < - 3 or X > 4
Answer:
hindi sulotion kung hindi man sorry nalang
walarin akong alam diyaan
Step-by-step explanation:
im sosory
