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2 years ago

7

- 2y + 7y + 4 Can someone help

1 answer:

sladkih [1.3K]2 years ago

6 0

Hi !
the answer is 5y+4

please let me know if im wrong (:

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In circle O, AD and BE are diameters.

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Answer:

B.) 132

Step-by-step explanation:

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2 years ago

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Decimal 0.002 fraction percent

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0.2% becouse
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2 years ago

The value of a motorbike depreciates by 32% per year. Work out the current value of a motorbike bought 5 years ago for £3600

DaniilM [7]

$\bf \qquad \textit{Amount for Exponential Decay}
\\\\
A=P(1 - r)^t\qquad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{initial amount}\to &3600\\
r=rate\to 32\%\to \frac{32}{100}\to &0.32\\
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\end{cases}
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3 years ago

You can spend up to $35 on a shopping trip.

VMariaS [17]

A. 35 greater than or equal to 14 + x
35 - 14 = 21
x = $21
b. If the shirt is 30% off it would cost $9.80
14 x 0.3 = 4.2
14 - 4.2 = 9.8
35 is greater than or equal to 9.80 + x
35 - 9.8 = 25.2
x = $25.20
This changes the inequality by making x greater than it was in part a
c. Yes, you do have enough money to buy the shirt that is on sale and a pair of pants. x is the amount that you have left to spend after you buy the shirt that is on sale. 25.20 is greater than the cost of the pants.

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2 years ago

The Venn diagram shows the results of two events resulting from rolling a number cube.

tankabanditka [31]

Answer:

$P(A|B)=\frac{2}{3}$

$P(A)*P(B)=\frac{1}{3}$

$P(A) =\frac{2}{3}$

$P(B) =\frac{1}{2}$ .

Step-by-step explanation:

We use the Venn diagram to calculate the desired probabilities.

Note that there are 6 possible results in the sample space

S = {1, 2, 3, 4, 5, 6}

Then note that in the region representing the intercept of A and B there are two possible values.

So

$P (A\ and\ B) = \frac{2}{6} = \frac{1}{3}$

In the region that represents event A there are 4 possible outcomes {4, 5, 1, 2}

So

$P(A) = \frac{4}{6} = \frac{2}{3}$

In the region that represents event B there are 3 possible outcomes {1, 2, 6}

So

$P(B) = \frac{3}{6} = \frac{1}{2}$ .

Now

$P(A | B)=\frac{P(A \ and\ B)}{P(B)}\\\\P(A | B)=\frac{\frac{1}{3}}{\frac{1}{2}}\\\\P(A|B)=\frac{2}{3}$

$P(A)*P(B)=\frac{2}{3}*\frac{1}{2}=\frac{1}{3}$

6 0

3 years ago