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3 years ago

Find the common difference 1, 201 , 401 , 601

Mathematics

1 answer:

Simora [160]3 years ago

5 0

The answer will be it adds up by 200

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Please help with these

MatroZZZ [7]

Set up a proportion.

$\frac{3~minutes}{2~questions}$ = $\frac{x~minutes}{12~questions}$

Cross multiply.

2x=36
x=12

It would take her 12 minutes.

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Formula for surface area of a cube: 6a² where a=20.

6 x (20)²
6 x 400
= 2400

Surface area: 2400 cm

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Mean absolute deviation: The average distance from each number in the set to the mean of the set.

Mean of the set: $\frac{(3+8+10+12+15)}{5} = \frac{48}{5} = 9.6$

9.6-3=6.6
9.6-8=1.6
10-9.6=0.4
12-9.6=11.4
15-9.6=5.4

Mean of 6.6, 1.6, 0.4, 11.4, and 5.4: $\frac{(6.6+1.6+0.4+11.4+5.4)}{5} = \frac{25.4}{5} = 5.08$

8 0

3 years ago

Rachel jogged along a trail that was 1/4 of a mile long. she jogged around the trail 8 times. How many mile did Rachel jogged?

Alex777 [14]

She jogged 2 miles, because 1/4 is 25%, if she ran the trail 8 times she ran the trail 1/4 * 8 which is 2 miles.

6 0

3 years ago

3.25 is what percent of 125?

melomori [17]

Answer:

4.0625

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

mr. devito was ordering pencils for apl fourth grade students. There are 118 fourth graders. Pencils come in packs of 6. He need

sweet [91]

Answer:

Mr. devito needs to buy 40 packs

Step-by-step explanation:

Given:

Total number of fourth grade students = 118

The number of pencils in one pack = 6

The number pencil each student gets =2

To find:

The number of packs of pencils that is to be bought = ?

Solution:

To give all the 118 fourth grade students each 2 pencils , the total number of pencils needed will be

= > $118 \times 2$

=> 236 Pencils

We know that a pack contains 6 pencils, so the number of pack that has to be bought , in order to have 236 pencils will be

=> $\frac{ \text{total number of pencils}}{\text{ number of pencils per pack }}$

On substituting the values

=> $\frac{236}{6}$

=> 39.33

=> 40

3 0

2 years ago

Three poultry farms B1, B2, and B3 supply chicken eggs to the same local market. The market performs some quality testing on the

ipn [44]

Answer:

a. 0.58

b. 0.78

Step-by-step explanation:

a. The probability of egg come from B1 or B2

P(B1) = 3000/10000 = 0.3

P(B2) = 4000/10000 = 0.4

P(P1 ∪ B2) = 0.3 + 0.4 -(0.3)(0.4)

P(P1 ∪ B2) = 0.7 - 0.12

P(P1 ∪ B2) = 0.58

b. The probability that the market received an egg that is acceptable

P(received an egg that is acceptable) = P(B1 acceptable) + P(B2 acceptable) + P(B3 acceptable)

P(received an egg that is acceptable) = 0.80*3000 + 0.90*4000 + 0.60*3000 / 10000

P(received an egg that is acceptable) = 2400 + 3600 + 1800 / 10000

P(received an egg that is acceptable) = 7800 / 10000

P(received an egg that is acceptable) = 0.78

4 0

3 years ago