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navik [9.2K]
3 years ago
14

3 cm and 9 mm converted completely into centimetres to one decimal place is ____cm. Someone please help me it would be greatly a

ppreciated :)
Mathematics
1 answer:
makvit [3.9K]3 years ago
3 0
9mm in centimeters is 0.9
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How did British scientists test Einstein theory of relativity
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Answer: Arthur Stanley Eddington's 1919 expedition confirmed Einstein's prediction for the deflection of light by the Sun during the total solar eclipse of 29 May 1919 which helped to cement the status of general relativity as a true theory. Since then many observations have confirmed the correctness of general relativity.

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8 0
3 years ago
In how many ways can the letters of the
GarryVolchara [31]

Answer: (b)

Step-by-step explanation:

Given

The letter "BHUTAN" has to be arranged

For filing the first place of 6 letter word, we have 6 choices

Similarly for filling the second place of the word, we have 5 choices as 1 letter is already filled.

In this way, the remaining places can be filled in 4, 3, 2, and 1 way

On combining the above, 6 places can be filled in  

\Rightarrow 6\times 5\times 4\times 3\times 2\times 1=6!\\\Rightarrow 720\ \text{ways}

Thus, option (b) is correct.

5 0
3 years ago
Please solve this problem. I can't solve it! And can someone explain how to do it please??
s2008m [1.1K]

Answer:

1.23

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6 0
3 years ago
a regular rectangular pyramid has a base and lateral faces that are congruent equilateral triangles. it has a lateral surface ar
Margarita [4]
A pyramid is regular if its base is a regular polygon, that is a polygon with equal sides and angle measures.
(and the lateral edges of the pyramid are also equal to each other)

Thus a regular rectangular pyramid is a regular pyramid with a square base, of side length say x.

The lateral faces are equilateral triangles of side length x.

The lateral surface area is 72 cm^2, thus the area of one face is 72/4=36/2=18  cm^2.

now we need to find x. Consider the picture attached, showing one lateral face of the pyramid.

by the Pythagorean theorem: 

h= \sqrt{ x^{2} - (x/2)^{2}}= \sqrt{ x^{2}- x^{2}/4}= \sqrt{3x^2/4}= \frac{ \sqrt{3} }{2}x

thus, 

Area_{triangle}= \frac{1}{2}\cdot base \cdot height\\\\18= \frac{1}{2}\cdot x \cdot \frac{ \sqrt{3} }{2}x\\\\ \frac{18 \cdot 4}{ \sqrt{3}}=x^2

thus:

x^2 =\frac{18 \cdot 4}{ \sqrt{3}}= \frac{18 \cdot 4 \cdot\  \sqrt{3} }{3}=24 \sqrt{3}       (cm^2)

but x^{2} is exactly the base area, since the base is a square of sidelength = x cm.


So, the total surface area = base area + lateral area =  24 \sqrt{3}+72   cm^2


Answer: 24 \sqrt{3}+72   cm^2

4 0
3 years ago
If f(x)=3^x+10 and g(x)=2x-4, find (f+g)(x)
Semmy [17]

Answer:

4

Step-by-step explanation:

5 0
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