Answer:
Option B. Amplitude =3 midline is y =2.
Step-by-step explanation:
In the graph attached we have to find the amplitude and midline of the periodic function.
Amplitude of the periodic function = (Distance between two extreme points on y asxis)/2
= (5-(-1))/2 = (5+1)/2 =6/2 =3.
Since amplitude of this function is 3 and by definition amplitude of any periodic function is the distance between the midline and the extreme point of wave on one side.
Therefore midline of the wave function is y=2 from which measurement of the amplitude is 3.
Answer:
<u>y = -2/3x + 5/6</u> (slope intercept) (y = ax + b)
4x + 6y = 5 (standard form) (Ax + By = C)
y - 3/2 = -2/3(x + 1) (point slope) (y-y1 = m(x-x1)) (m = y2 - y1 / x2 - x1)
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Answer:
(x-6)(x-4) = 0
Step-by-step explanation:
Subtract 5 from both sides to make the equation equal to 0. You will get the equation x2-10x+24=0. Now think of two numbers that multiply to get 24 but add to get -10. These numbers are -6 and -4. The factors of x2 are x and x which multiply to get x2. Now put two linear factors into parathesis to get (x-6)(x-4) = 0.
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