See the picture attached to better understand the problem
we know that
If two secant segments are drawn to a <span>circle </span><span>from an exterior point, then the product of the measures of one secant segment and its external secant segment is equal to the product of the measures of the other secant segment and its external secant segment.
</span>so
jl*jk=jn*jm------> jn=jl*jk/jm
we have
<span>jk=8,lk=4 and jm=6
</span>jl=8+4----> 12
jn=jl*jk/jm-----> jn=12*8/6----> jn=16
the answer isjn=16
Answer: The lamppost is 7 feet 2 inches
Step-by-step explanation: If Ann measured her own height and her shadow, then what she used is a ratio between both measurements. If she can measure the shadow of the lamppost, then she can use the same ratio of her height and it’s shadow to derive the correct measurement of the lamppost.
If Ann’s height was measured as 5 feet 3 inches, and her shadow was 8 feet 9 inches, the ratio between them can be expressed as 3:5.
Reduce both dimensions to the same unit, that is, inches. (Remember 12 inches = 1 foot)
Ratio = 63/105
Reduce to the least fraction
Ratio = 3/5
If the height of the lamppost is H, then
H/144 = 3/5
H = (144 x3)/5
H = 86.4
Therefore the lamppost is approximately 86 inches, that is 7 feet and 2 inches tall.
A because it start at 20 and divided 1/2 each time. And when you solved 2/ 1/2 , you get 4 and that is correct because you have 4 arrows.