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3 years ago

I need help learning about slopes of lines

1 answer:

4 0

To find the slope use the rate of change in y/the rate of change in x or you can use y2-y1/x2-x1
Use this website to help you.
http://www.coolmath.com/precalculus-review-calculus-intro/precalculus-algebra/01-graphing-slopes-of-lines-01

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Scores on the math portion of the SAT are believed to be normally distributed and range from 200 to 800. A researcher from the a

Doss [256]

Using the z-distribution, it is found that she should take a sample of 46 students.

<h3>What is a z-distribution confidence interval?</h3>

The confidence interval is:

$\overline{x} \pm z\frac{\sigma}{\sqrt{n}}$

The margin of error is:

$M = z\frac{\sigma}{\sqrt{n}}$

In which:

$\overline{x}$ is the sample mean.

z is the critical value.

n is the sample size.

$\sigma$ is the standard deviation for the population.

In this problem, we have a 95% confidence level, hence $\alpha = 0.95$ , z is the value of Z that has a p-value of $\frac{1+0.95}{2} = 0.975$ , so the critical value is z = 1.96.

Scores on the math portion of the SAT are believed to be normally distributed and range from 200 to 800, hence, by the Empirical Rule the standard deviation is found as follows:

$6\sigma = 800 - 200$

$6\sigma = 600$

$\sigma = 100$

The sample size is n when M = 29, hence:

$M = z\frac{\sigma}{\sqrt{n}}$

$29 = 1.96\frac{100}{\sqrt{n}}$

$29\sqrt{n} = 196$

$\sqrt{n} = \frac{196}{29}$

$(\sqrt{n})^2 = \left(\frac{196}{29}\right)^2$

n = 45.67.

Rounding up, a sample of 46 students should be taken.

More can be learned about the z-distribution at brainly.com/question/25890103

#SPJ1

4 0

2 years ago

Quantitative noninvasive techniques are needed for routinely assessing symptoms of peripheral neuropathies, such as carpal tunne

Marizza181 [45]

Answer

test statistic $t = -2.27$

P-value $p- value = 0.0198$

Step-by-step explanation:

From the question we are told that

The first sample size is $n_1 = 5$

The first sample mean is $\= x_1 = 1.76 \ mm$

The first standard is $s_1 = 0.55$

The second is $sample \ size\ is\ n_2 = 11$

The second sample mean is $\= x_2 = 2.56$

The second standard deviation is $\sigma = 0.84$

The level of significance is $\alpha = 0.01$

The null hypothesis is $H_o : \mu_1 - \mu_2 = 0$

The alternative hypothesis is $H_a: \mu_1 - \mu_2 < 0$

Generally the test statistics is mathematically represented as

$t = \frac{ (\= x _1 - \= x_2) - ( \mu_1 - \mu_2)}{ \sqrt{\frac{s_1 ^2 }{ n_1 } + \frac{s_1 ^2 }{ n_1 } } }$

=> $t = \frac{ (1.76 - 2.56 ) - 0 }{ \sqrt{\frac{0.55^2 }{ 5 } + \frac{0.84^2 }{11 } } }$

=> $t = -2.27$

Generally degree of freedom is mathematically represented as

$df = n_1 + n_2 - 2$

=> $df = 5 + 11 - 2$

=> $df = 14$

From the student t distribution table the probability value to the left that corresponds to $t = -2.27$ at a degree of freedom of $df = 14$ is

$p- value = 0.0198$

6 0

3 years ago

Select all that apply.

garik1379 [7]

All but the first statement are true.

_____
In the equation y=kx, "slope" is the coefficient of x, thus y=-3x.

8 0

3 years ago

The amount of time it takes for a student to complete a statistics quiz is uniformly distributed (or, given by a random variable

tresset_1 [31]

Answer:

A. This is possible but less likely

B. This is very possible

C. This is highly unlikely

B. is the most possible A. is the second most possible C. is least possible

Hope this helps <33

6 0

3 years ago

I need help plz #12 plz I don’t understand

Trava [24]

We can say that because 3 times 9, which would equal 27, could be the same as 4*9, which would be 36. So Pat needs 36 pints of green paint. Down below is a tape diagram so you can see what it is.

8 0

3 years ago